postgresql - 返回作为保留关键字的表列名称？

Question

我正在创建这个返回表格的函数。我在下面代码的第 9 行有这个问题，我认为“位置”和下面的“属性”列是主要问题。我想像下面的代码一样返回列名。任何人都可以帮助我吗？提前致谢！

  CREATE OR REPLACE FUNCTION acc_qry_chart_of_account ( 
  type CHARACTER (3)='GL') RETURNS TABLE ( seqno SERIAL,
        acc_id INTEGER,
        parent_code CHARACTER (20),
        acc_code CHARACTER (20),
        description CHARACTER VARYING (120),
        description2 CHARACTER VARYING (120),
        acclevel INTEGER,
        position CHARACTER VARYING (120),
        attribute INTEGER,
        acctype CHARACTER (3),
        exttype CHARACTER(3)
  )
AS $$
DECLARE
....
BEGIN
....
END;
$$ LANGUAGE 'plpgsql'

Answer 1

你可以这样解决。2 变化。

• 双引号列位置
• 将 seqno 声明为整数。Serial 不是数据类型（它是使用序列的快捷方式）

新功能：

  CREATE OR REPLACE FUNCTION acc_qry_chart_of_account ( 
  type CHARACTER (3)='GL') RETURNS TABLE ( seqno integer,
        acc_id INTEGER,
        parent_code CHARACTER (20),
        acc_code CHARACTER (20),
        description CHARACTER VARYING (120),
        description2 CHARACTER VARYING (120),
        acclevel INTEGER,
        "position" CHARACTER VARYING (120),
        attribute INTEGER,
        acctype CHARACTER (3),
        exttype CHARACTER(3)
  )
AS $$
DECLARE
....
BEGIN
....
END;
$$ LANGUAGE 'plpgsql'