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我查看了RxJS 5 combineLatest的源代码，发现了许多带有编号参数的调用排列。

为什么在有剩余参数时会这样做？

TypeScript 是否有任何即将推出的功能可以让这变得不那么冗长？

我想知道这是否与输入其余参数或智能感知有关？

export interface CombineLatestSignature<T> {
  <R>(project: (v1: T) => R): Observable<R>;
  <T2, R>(v2: ObservableInput<T2>, project: (v1: T, v2: T2) => R): Observable<R>;
  <T2, T3, R>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, project: (v1: T, v2: T2, v3: T3) => R): Observable<R>;
  <T2, T3, T4, R>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>, project: (v1: T, v2: T2, v3: T3, v4: T4) => R): Observable<R>;
  <T2, T3, T4, T5, R>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>, v5: ObservableInput<T5>, project: (v1: T, v2: T2, v3: T3, v4: T4, v5: T5) => R): Observable<R>;
  <T2, T3, T4, T5, T6, R>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>, v5: ObservableInput<T5>, v6: ObservableInput<T6>, project: (v1: T, v2: T2, v3: T3, v4: T4, v5: T5, v6: T6) => R): Observable<R>;

  <T2>(v2: ObservableInput<T2>): Observable<[T, T2]>;
  <T2, T3>(v2: ObservableInput<T2>, v3: ObservableInput<T3>): Observable<[T, T2, T3]>;
  <T2, T3, T4>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>): Observable<[T, T2, T3, T4]>;
  <T2, T3, T4, T5>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>, v5: ObservableInput<T5>): Observable<[T, T2, T3, T4, T5]>;
  <T2, T3, T4, T5, T6>(v2: ObservableInput<T2>, v3: ObservableInput<T3>, v4: ObservableInput<T4>, v5: ObservableInput<T5>, v6: ObservableInput<T6>): Observable<[T, T2, T3, T4, T5, T6]>;

  <R>(...observables: Array<ObservableInput<any> | ((...values: Array<any>) => R)>): Observable<R>;
  <R>(array: ObservableInput<any>[]): Observable<R>;
  <R>(array: ObservableInput<any>[], project: (...values: Array<any>) => R): Observable<R>;
}
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1 回答 1

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休息参数都必须用相同的类型声明，所以不可能只用休息参数准确地建模这个特定的接口。我看不出有任何方法可以在不丢失有用的类型信息的情况下使这个接口不那么冗长。

于 2016-02-20T11:25:28.570 回答