php - 查询没有得到任何结果

Question

我正在让我的查询显示结果，我在 mySQL 中本地运行了完全相同的查询，我得到了想要的结果，但是当它通过以下代码执行时没有任何反应。

$JobID = '3214.GF.010.J45.TEA';
$ProjectID = '3214';    
$conn = new mysqli ($server,$username,$password,$dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
echo "Connected successfully <br>";
$stmt = $conn->prepare('Select jmpPartShortDescription, ujmpLevel, ujmpRoom, jmpClosed from Inf_Jobs');
//$stmt->bind_param('ss',$JobID,$ProjectID);
$stmt -> bind_result($Description,$Level,$Room,$Closed);
$stmt -> fetch();
$stmt -> close();
$conn -> close();

echo $Description .$Level .$Room .$Closed;

我不明白为什么我没有得到任何结果我收到连接成功消息但没有返回实际值。

Answer 1

你需要execute()一个准备好的声明来让它做任何事情。

$stmt = $conn->prepare('Select jmpPartShortDescription, ujmpLevel, ujmpRoom, jmpClosed from Inf_Jobs');
//$stmt->bind_param('ss',$JobID,$ProjectID);

$stmt->execute(); // <- this is what does the work

$stmt -> bind_result($Description,$Level,$Room,$Closed);
$stmt -> fetch();