-2

我想了解这种转换究竟是如何发生的。

http://www8.cs.umu.se/~isak/Snippets/a2e.c

/*
**  ASCII <=> EBCDIC conversion functions
*/

static unsigned char a2e[256] = {
          0,  1,  2,  3, 55, 45, 46, 47, 22,  5, 37, 11, 12, 13, 14, 15,
         16, 17, 18, 19, 60, 61, 50, 38, 24, 25, 63, 39, 28, 29, 30, 31,
         64, 79,127,123, 91,108, 80,125, 77, 93, 92, 78,107, 96, 75, 97,
        240,241,242,243,244,245,246,247,248,249,122, 94, 76,126,110,111,
        124,193,194,195,196,197,198,199,200,201,209,210,211,212,213,214,
        215,216,217,226,227,228,229,230,231,232,233, 74,224, 90, 95,109,
        121,129,130,131,132,133,134,135,136,137,145,146,147,148,149,150,
        151,152,153,162,163,164,165,166,167,168,169,192,106,208,161,  7,
         32, 33, 34, 35, 36, 21,  6, 23, 40, 41, 42, 43, 44,  9, 10, 27,
         48, 49, 26, 51, 52, 53, 54,  8, 56, 57, 58, 59,  4, 20, 62,225,
         65, 66, 67, 68, 69, 70, 71, 72, 73, 81, 82, 83, 84, 85, 86, 87,
         88, 89, 98, 99,100,101,102,103,104,105,112,113,114,115,116,117,
        118,119,120,128,138,139,140,141,142,143,144,154,155,156,157,158,
        159,160,170,171,172,173,174,175,176,177,178,179,180,181,182,183,
        184,185,186,187,188,189,190,191,202,203,204,205,206,207,218,219,
        220,221,222,223,234,235,236,237,238,239,250,251,252,253,254,255
};

static unsigned char e2a[256] = {
          0,  1,  2,  3,156,  9,134,127,151,141,142, 11, 12, 13, 14, 15,
         16, 17, 18, 19,157,133,  8,135, 24, 25,146,143, 28, 29, 30, 31,
        128,129,130,131,132, 10, 23, 27,136,137,138,139,140,  5,  6,  7,
        144,145, 22,147,148,149,150,  4,152,153,154,155, 20, 21,158, 26,
         32,160,161,162,163,164,165,166,167,168, 91, 46, 60, 40, 43, 33,
         38,169,170,171,172,173,174,175,176,177, 93, 36, 42, 41, 59, 94,
         45, 47,178,179,180,181,182,183,184,185,124, 44, 37, 95, 62, 63,
        186,187,188,189,190,191,192,193,194, 96, 58, 35, 64, 39, 61, 34,
        195, 97, 98, 99,100,101,102,103,104,105,196,197,198,199,200,201,
        202,106,107,108,109,110,111,112,113,114,203,204,205,206,207,208,
        209,126,115,116,117,118,119,120,121,122,210,211,212,213,214,215,
        216,217,218,219,220,221,222,223,224,225,226,227,228,229,230,231,
        123, 65, 66, 67, 68, 69, 70, 71, 72, 73,232,233,234,235,236,237,
        125, 74, 75, 76, 77, 78, 79, 80, 81, 82,238,239,240,241,242,243,
         92,159, 83, 84, 85, 86, 87, 88, 89, 90,244,245,246,247,248,249,
         48, 49, 50, 51, 52, 53, 54, 55, 56, 57,250,251,252,253,254,255
};

char ASCIItoEBCDIC(const unsigned char c)
{
        return a2e[c];
}

char EBCDICtoASCII(const unsigned char c)
{
        return e2a[c];
}

在示例 text 的情况下char sample[6] = "hello";，如何准确h地从asciito转换，ebcdic反之亦然？

编辑：我真的不需要转换字符串。我只想知道这些表是如何构建的。

4

2 回答 2

2

我只想知道这些表是如何构建的。

'0'ASCII中的代码值为48。EBCDIC
'0'中的代码值为 240。

所以我们需要将 48 映射到 240 和 240 到 48 的表。

'0'使用ASCII码值 48 进行转换。a2e[48]返回字符240的EBCDIC码'0'。 

static unsigned char a2e[256] = {
    ...
    ...
    ...
    240,241,242,243,244,245,246,247,248,249,122, 94, 76,126,110,111,
    ...

现在使用 240，即字符的 EBCDIC 代码'0'。 e2a[240]它返回48字符的 ASCII 码'0'。

static unsigned char e2a[256] = {
     ...
     13 more rows
     ...
     48, 49, 50, 51, 52, 53, 54, 55, 56, 57,250,251,252,253,254,255
};

对所有其他常见字符执行此操作。为其余部分定义映射。回想一下，ASCII 只定义了 128 个字符，而 EBCDIC 定义了 256 个字符。

杂项

EBCDIC 布局与一些打孔卡有一定的关系。

在这两个字符集中，字符0, 1, ...9是连续的——这是 C 中编码的要求。

在这两组中，大写和小写字母相差 1 位，因此可以编写以下代码（最好使用 C's tolower()）

int from_upper_to_lower(int code) {
  return code - 'A' + 'a`;
}
于 2016-02-18T21:44:20.793 回答
0

从一种字符集转换为另一种字符集的函数可以使用这些表在汇编程序中编写。

在 C 中，您可以将此字符串从 ASCII 转换为 EBCDIC

char sample[6] = "hello";

以下方式

char * AsciiToEbcdic( char *s )
{
    for ( char *p = s; *p; ++p ) *p = a2e[( unsigned char )*p];

    return s;
}

前提是该表可在函数中访问。

这是一个演示程序。

#include <stdio.h>

char * AsciiToEbcdic( char *s )
{
    static unsigned char a2e[256] = 
    {
          0,  1,  2,  3, 55, 45, 46, 47, 22,  5, 37, 11, 12, 13, 14, 15,
         16, 17, 18, 19, 60, 61, 50, 38, 24, 25, 63, 39, 28, 29, 30, 31,
         64, 79,127,123, 91,108, 80,125, 77, 93, 92, 78,107, 96, 75, 97,
        240,241,242,243,244,245,246,247,248,249,122, 94, 76,126,110,111,
        124,193,194,195,196,197,198,199,200,201,209,210,211,212,213,214,
        215,216,217,226,227,228,229,230,231,232,233, 74,224, 90, 95,109,
        121,129,130,131,132,133,134,135,136,137,145,146,147,148,149,150,
        151,152,153,162,163,164,165,166,167,168,169,192,106,208,161,  7,
         32, 33, 34, 35, 36, 21,  6, 23, 40, 41, 42, 43, 44,  9, 10, 27,
         48, 49, 26, 51, 52, 53, 54,  8, 56, 57, 58, 59,  4, 20, 62,225,
         65, 66, 67, 68, 69, 70, 71, 72, 73, 81, 82, 83, 84, 85, 86, 87,
         88, 89, 98, 99,100,101,102,103,104,105,112,113,114,115,116,117,
        118,119,120,128,138,139,140,141,142,143,144,154,155,156,157,158,
        159,160,170,171,172,173,174,175,176,177,178,179,180,181,182,183,
        184,185,186,187,188,189,190,191,202,203,204,205,206,207,218,219,
        220,221,222,223,234,235,236,237,238,239,250,251,252,253,254,255
    };

    for ( char *p = s; *p; ++p ) *p = a2e[( unsigned char )*p];

    return s;
} 

int main( void ) 
{
    char s[] = "@@@@@";

    printf( "\"%s\"\n", s );
    printf( "\"%s\"\n", AsciiToEbcdic( s ) );

    return 0;
}

它的输出是

"@@@@@"
"|||||"
于 2016-02-19T00:16:35.900 回答