我正在玩解析(PostgreSQL)日志,这些日志可以包含多行条目。
2016-01-01 01:01:01 entry1
2016-01-01 01:01:02 entry2a
entry2b
2016-01-01 01:01:03 entry3
所以 - 使用 Perl 或 Python 脚本,我只需抓取下一行,如果它不是以时间戳开头,则将其附加到上一个日志条目。什么是一种明智的方法来解决这个attoparsec
问题io-streams
?我显然想用lookAhead
时间戳做某事但未能匹配时间戳,但我的大脑只是错过了一些东西。
不——还是看不到。我已经剥夺了我所拥有的。解析一行很容易。我不知道如何解析“最多”另一个解析模式 - 我可以看到我可以使用的 lookAhead 函数,但我看不出它如何适合应用“非”条件。
我也看不出我怎么能匹配。完全有可能我的大脑已经卡住了。
{-# LANGUAGE OverloadedStrings #-}
module DummyParser (
LogStatement (..), parseLogLine
-- and, so we can test it...
, LogTimestamp , parseTimestamp
, parseSqlStmt
, newLineAndTimestamp
) where
{- we want to parse...
TIME001 statement: SELECT true;
TIME002 statement: SELECT 'b',
'c';
TIME003 statement: SELECT 3;
-}
import Data.Attoparsec.ByteString.Char8
import qualified Data.ByteString.Char8 as B
type LogTimestamp = Int
data LogStatement = LogStatement {
l_ts :: LogTimestamp
,l_sql :: String
} deriving (Eq, Show)
restOfLine :: Parser B.ByteString
restOfLine = do
rest <- takeTill (== '\n')
isEOF <- atEnd
if isEOF then
return rest
else
(char '\n') >> return rest
-- e.g. TIME001
parseTimestamp :: Parser LogTimestamp
parseTimestamp = do
string "TIME"
digits <- count 3 digit
return (read digits)
-- e.g. statement: SELECT 1
parseSqlStmt :: Parser String
parseSqlStmt = do
string "statement: "
-- How can I match until the next timestamp?
sql <- restOfLine
return (B.unpack sql)
newLineAndTimestamp :: Parser LogTimestamp
newLineAndTimestamp = (char '\n') *> parseTimestamp
spaces :: Parser ()
spaces = do
skipWhile (== ' ')
-- e.g. TIME001 statement: SELECT * FROM schema.table;
parseLogLine :: Parser LogStatement
parseLogLine = do
log_ts <- parseTimestamp
spaces
log_sql <- parseSqlStmt
let ls = LogStatement log_ts log_sql
return ls
编辑:所以,这就是我最终得到的结果,感谢箭头的帮助
isTimestampNext = lookAhead parseTimestamp *> pure()
parseLogLine :: Parser LogStatement
parseLogLine = do
log_ts <- parseTimestamp
spaces
log_sql <- parseSqlStmt
extraLines <- manyTill restOfLine (endOfInput <|> isTimestampNext)
let ls = LogStatement log_ts (log_sql ++ (B.unpack $ B.concat extraLines))
return ls