3

这让我发疯（发疯！）。构建/运行文件正确且 fmt 命令正确。但是，如果我尝试合并到一个任务文件中，它就会停止工作。

这两个工作正常，并按照我想要的方式行事：

任务.json

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"taskName": "build",
"args": [
    "build",
    "-o",
    "${workspaceRoot}.exe",
    "&&",
    "${workspaceRoot}.exe"
],
"isBuildCommand": true
}

任务.json

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"taskName": "fmt",
"args": [
    "fmt",
    "${file}"
],
"isBuildCommand": true
}

但是合并到一个文件中，它将不起作用：

任务.json

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"tasks": [
    {
        "taskName": "build",
        "args": [
            "build",
            "-o",
            "${workspaceRoot}.exe",
            "&&",
            "${workspaceRoot}.exe"
        ],
        "isBuildCommand": true
    },
    {
        "taskName": "fmt",
        "args": [
            "fmt",
            "${file}"
        ]
    }
]
}

构建时给出的错误：

can't load package: package build: cannot find package "build" in any of:
    D:\dev\Go\src\build (from $GOROOT)
    D:\dev\Gopher\src\build (from $GOPATH)
can't load package: package -o: cannot find package "-o" in any of:
    D:\dev\Go\src\-o (from $GOROOT)
    D:\dev\Gopher\src\-o (from $GOPATH)
can't load package: package d:/dev/Gopher/src/myproject.exe: cannot find package "d:/dev/Gopher/src/myproject.exe" in any of:
    D:\dev\Go\src\d:\dev\Gopher\src\myproject.exe (from $GOROOT)
    D:\dev\Gopher\src\d:\dev\Gopher\src\myproject.exe (from $GOPATH)

我似乎无法理解为什么它以一种方式工作，但不能以另一种方式工作。此处概述了第二种方法（用于组合任务）：在 VSCode 中定义多个任务

回答：问题在于添加“build”或“fmt”作为参数，而它已经被列为任务名称。我不知道 taskname 是这样工作的。最终的工作产品，允许用户开发而不用担心愚蠢的 Windows 防火墙：

tasks.json （感谢@not-a-golfer 的最终和工作）

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"echoCommand": true ,
"tasks": [
    {
        "taskName": "build",
        "args": [
            "-o",
            "${workspaceRoot}.exe",
            "&&",
            "${workspaceRoot}.exe"
        ],
        "isBuildCommand": true
    },
    {
        "taskName": "fmt",
        "args": [
            "${file}"
        ]
    }
]
}
4

3 回答 3

3

以下似乎有效，但您似乎无法将运行链接&&：

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"echoCommand": true ,
"tasks": [
    {
        "taskName": "build",
        "args": [
            "-x",
            "-o",
            "${workspaceRoot}.exe"
        ],
        "isBuildCommand": true
    },
    {
        "taskName": "fmt",
        "args": [
            "${file}"
        ]
    }
]
}
于 2016-02-11T17:25:50.337 回答
0

您应该添加属性suppressTaskName。

删除多余参数的 OPs 解决方案build显然有效，但是，VSCode 的文档涵盖了这个示例：

我们设置suppressTaskName为 true，因为默认情况下任务名称也会传递给命令，这将导致“echo hello Hello World”。

{
    "version": "0.1.0",
    "command": "echo",
    "isShellCommand": true,
    "args": [],
    "showOutput": "always",
    "echoCommand": true,
    "suppressTaskName": true,
    "tasks": [
        { 
            "taskName": "hello",
            "args": ["Hello World"]
        },
        { 
            "taskName": "bye",
            "args": ["Good Bye"]
        }
    ]
}
于 2016-10-15T09:13:55.573 回答
0

我最喜欢的构建任务是：

{
"version": "0.1.0",
"isShellCommand": true,
"showOutput": "always",
"command": "go",
"echoCommand": true ,
"options": {
    "cwd": "${fileDirname}"
},
"tasks": [
    {
        "taskName": "build",
        "args": [
            "build",
            "-x"
        ],
        "isBuildCommand": true,
        "suppressTaskName": true
    }
]
}
于 2017-05-01T07:14:38.497 回答