4

我需要为通过 PHP 购买金额等于或大于 100 欧元的会员分配一种“高级状态”。

已经设置了条件操作（用户 = 匿名/经过身份验证并且总金额 = 等于/大于 100 并且用户 =！溢价）但我错过了 PHP 部分来实际说“然后授予他高级会员资格”。

我怎样才能做到这一点？

编辑：下面的代码正确吗？

if ($account) {
  $uid = $account->uid;
  $role_name = 'authenticated user';
  $rid = db_result(db_query("SELECT rid FROM {role} WHERE name = '%s'", $role_name));
  db_query("INSERT INTO {users_roles} (uid, rid) VALUES(%d, %d)", $uid, $rid);
  watchdog('user', 'uc ca added role to Ubercart created user');
}
4

4 回答 4

6

你可以用user_load()and做到这一点user_save()：

$uid = 1; // UID of user to add role to
$role_name = 'test role'; // Name of role to add

// Get RID of role
$rid = db_result(db_query("SELECT r.rid FROM {role} r WHERE r.name = '%s'", $role_name));

// Load user object
$account = user_load(array('uid' => 1));

// Save the user object with the new roles.
if ($account !== FALSE && !isset($account->roles[$rid])) {
  $roles = $account->roles + array($rid => $role_name);
  user_save($account, array('roles' => $roles));
}

如果您想为多个用户批量执行此操作，则有user_multiple_role_edit()：

$uids = array(1, 2, 3, 4); // UIDs of users to add role to
$role_name = 'test role'; // Name of role to add

// Get RID of role
$rid = db_result(db_query("SELECT r.rid FROM {role} r WHERE r.name = '%s'", $role_name));

// Add the role to UIDs
user_multiple_role_edit($uids, 'add_role', $rid);

编辑

如果您想为当前用户执行此操作（就像您在评论中提到的检查的一部分），您可以执行以下操作：

// Check for value over 100.00
if ($total_value > 100) {
  global $user; // Retrieve user object for currently logged in user.

  $role_name = 'test role'; // Name of role to add

  // Get RID of role
  $rid = db_result(db_query("SELECT r.rid FROM {role} r WHERE r.name = '%s'", $role_name));

  // Save the user object with the new role.
  if (!isset($user->roles[$rid])) {
    $roles = $user->roles + array($rid => $role_name);
    user_save($user, array('roles' => $roles));
  }
}
// Other code here.
于 2010-08-20T18:11:05.277 回答
3

尽管我会更新 Drupal 7 的代码段。否则它可以正常工作:)

$rid = db_query("SELECT r.rid FROM {role} r WHERE r.name = :rname", 
                array(':rname' => $role_name))->fetchField();
于 2013-03-12T16:03:28.647 回答
2

我宁愿使用user_role_load_by_name函数。

于 2013-05-21T23:31:02.463 回答
0

对于 Drupal 7：

     global $user; // Retrieve user object for currently logged in user.

  $role_name = 'test role'; // Name of role to add

  // Get RID of role
  $rid = db_query("SELECT r.rid FROM {role} r WHERE r.name = :rname", array(':rname' => $role_name))->fetchField();

  // Save the user object with the new role.
  if (!isset($user->roles[$rid])) {
    $roles = $user->roles + array($rid => $role_name);
    user_save($user, array('roles' => $roles));
  }

谢谢瑞克斯。

于 2013-08-30T06:49:50.667 回答