1

我收到此错误：

Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS `Colleges__*` FROM college_admins CollegeAdmins LEFT JOIN colleges Colleges O' at line 1

这是给出此错误的 SQL 查询：

SELECT Colleges.* AS `Colleges__*` FROM college_admins CollegeAdmins LEFT JOIN colleges Colleges ON Colleges.id = (CollegeAdmins.college_id) WHERE CollegeAdmins.user_id = :c0 LIMIT 20 OFFSET 0

我启用了 quoteIdentifiers config\app，但它导致了这个新错误：

Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS `Colleges__*` FROM `college_admins` `CollegeAdmins` LEFT JOIN `colleges` `Col' at line 1

查询变为：

SELECT `Colleges`.* AS `Colleges__*` FROM `college_admins` `CollegeAdmins` LEFT JOIN `colleges` `Colleges` ON `Colleges`.`id` = (`CollegeAdmins`.`college_id`) WHERE `CollegeAdmins`.`user_id` = :c0 LIMIT 20 OFFSET 0

我认为它将“Col from Colleges”作为关键字“COL”，但我不确定。如何解决这个问题？

这是生成 MySQL 查询的 CakePHP 代码：

return $college_admins->find()
    ->select(['Colleges.*'])
    ->leftJoinWith('Colleges')
    ->where(['CollegeAdmins.user_id' => $userId]);
4

2 回答 2

1

您不能Colleges.*在 CakePHP ORM 查询 (CakePHP 3.x) 中使用。正如您所发现的，这会创建不正确的 SQL 别名，例如Colleges__*. 而不是选择表的所有列，您需要传递一个表对象。

所以你可能想要做类似的事情： -

->select($college_admins->Colleges)

假设Colleges与您的CollegeAdmins表相关联。

于 2016-02-10T16:34:55.747 回答
0

您不能为 Colleges.* 设置别名，因为这指的是 Colleges 表中的所有列，而别名指的是单个列（或表或子查询）。您需要列出 Colleges 表中的所有字段并为每个字段提供别名，例如

select colleges.ig as colleges_id, colleges.field1 as colleges_field1, ...

sql 中没有以这种方式提供别名的语法。您可能会尝试在 php 中访问 mysql 返回的元数据以检索每个字段的表名。

于 2016-02-10T15:02:34.753 回答