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我使用 xpath 表达式/abcde/response从 xml成功检索响应数据,

<abcde>
            <response>000</response>
</abcde>

但无法从相同的 xml中检索响应数据,但有一些附加数据

<abcde version="8.1" xmlns="http://www.litle.com/schema"
      response="0" message="Valid Format">
            <response>000</response>
</abcde>

我究竟做错了什么 ?

4

1 回答 1

2
package stackoverflow;
import java.io.ByteArrayInputStream;
import java.util.HashMap;
import java.util.Map;
import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.DocumentFactory;
import org.dom4j.DocumentHelper;
import org.dom4j.XPath;
import org.dom4j.io.SAXReader;
import org.dom4j.xpath.DefaultXPath;
import org.jaxen.VariableContext;

public class MakejdomWork {
    public static void main(String[] args) {
        new MakejdomWork().run();
    }

    public void run() {
        ByteArrayInputStream bis = new ByteArrayInputStream("<abcde version=\"8.1\" xmlns=\"http://www.litle.com/schema\"      response=\"0\" message=\"Valid Format\">            <response>000</response></abcde>".getBytes());
        //ByteArrayInputStream bis = new ByteArrayInputStream("<abcde><response>000</response></abcde>".getBytes());

        Map nsPrefixes = new HashMap();
        nsPrefixes.put( "x", "http://www.litle.com/schema" );

        DocumentFactory factory = new DocumentFactory();
        factory.setXPathNamespaceURIs( nsPrefixes );

        SAXReader reader = new SAXReader();
        reader.setDocumentFactory( factory );
        Document doc;
        try {
            doc = reader.read( bis );
            Object value = doc.valueOf("/abcde/x:response");
            System.out.println(value);
        } catch (DocumentException e) {
            e.printStackTrace();
        }
    }
}

简短的回答:如果您的解析器支持命名空间(dom4j 是),则需要使用命名空间前缀

于 2011-06-03T15:39:59.993 回答