4

我正在从事一个涉及使用 cURL 或 file_get_contents 获取页面的项目。问题是当我尝试回显获取的 html 时，输出似乎与原始页面不同，并非所有图像都显示出来。请我想知道是否有解决方案。我的代码

    <?php
    //Get the url
    $url = "http://www.google.com";

    //Get the html of url
    function get_data($url) 
    { 
       $ch = curl_init();
       $timeout = 5;
       //$userAgent = "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US)AppleWebKit/525.13 (KHTML, like Gecko) Chrome/0.X.Y.Z Safari/525.13.";
       $userAgent = "IE 7 – Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.04506.30)";
      curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);
      curl_setopt($ch, CURLOPT_FAILONERROR, true);
      curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
      curl_setopt($ch, CURLOPT_AUTOREFERER, true);
      curl_setopt($ch, CURLOPT_TIMEOUT, 10);
      curl_setopt($ch,CURLOPT_URL,$url);
      curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
      curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
      $data = curl_exec($ch);
      curl_close($ch);
      return $data;

    }

    $html = file_get_contents($url);
    echo $html;
?>

谢谢

4

2 回答 2

8

您应该使用<base>为所有相对链接指定一个基本 url：

如果你 curlhttp://example.com/thisPage.html然后base在你的回显输出中添加一个标签''。从技术上讲，这应该在 中<head>，但这会起作用：

echo '<base href="http://example.com/" />';
echo $html;

现场示例 w<base>已损坏 w/o<base>

于 2010-08-19T08:09:01.777 回答
1

用这个 

    //Get the html of url
    function get_data($url) 
    { 
       $ch = curl_init();
       $timeout = 5;
       //$userAgent = "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US)AppleWebKit/525.13 (KHTML, like Gecko) Chrome/0.X.Y.Z Safari/525.13.";
       $userAgent = "IE 7 – Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.04506.30)";
      curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);
      curl_setopt($ch, CURLOPT_FAILONERROR, true);
      curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
      curl_setopt($ch, CURLOPT_AUTOREFERER, true);
      curl_setopt($ch, CURLOPT_TIMEOUT, 10);
      curl_setopt($ch,CURLOPT_URL,$url);
      curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
      curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
      $data = curl_exec($ch);
      curl_close($ch);
      return $data;

    }

$parse = parse_url($url);
$count =  "http://".$parse['host'].dirname($parse['path'])."//";

$page = str_replace("<head>", "<head>\n<base href=\"" . $count . "\" />", $page);
$page = str_replace("<HEAD>", "<head>\n<base href=\"" . $count . "\" />", $page);
echo $page;
?>
于 2011-02-21T16:20:15.427 回答