4

我目前有代码:

$('.example').bind('DOMNodeInserted DOMNodeRemoved', function(event) {
    ....
});

效果很好,但效率不高,此后已被弃用。有什么更好的方法来做到这一点?

我一直在研究 MutationObserver 但这段代码有效吗?

它给出了错误“mutation.addedNodes不是函数”,我也需要removedNodes我意识到。

var observer = new MutationObserver(function(mutations) {
      mutations.forEach(function(mutation) {
        mutation.addedNodes.forEach(function(node) {
          if (node.className == 'example') {
              ....
          }
        });
      });
    });
    observer.observe(document, {
      childList: true,
      subtree: true,
      attributes: false,
      characterData: false,
    });
4

1 回答 1

2

.addedNodes返回 a NodeListnot an Array,它没有.forEach()方法。尝试使用Array.prototype.slice()to cast .addedNodesto an Arraywhich has method.forEach()

var observer = new MutationObserver(function(mutations) {
      mutations.forEach(function(mutation) {
        var nodes = Array.prototype.slice.call(mutation.addedNodes);
        nodes.forEach(function(node) {
          if (node.parentElement.className == "example") {
              alert(node.parentElement.className)
          }
        });
      });
    });
    observer.observe(document.querySelector(".example"), {
      childList: true,
      subtree: true,
      attributes: false,
      characterData: false,
    });

var el = document.createElement("div");
el.className = "example-child";
document.querySelector(".example").appendChild(el)
<div class="example"></div>

于 2016-01-28T15:29:47.770 回答