265

我正在试验这种代码优先的方法,但我现在发现 System.Decimal 类型的属性被映射到 decimal(18, 0) 类型的 sql 列。

如何设置数据库列的精度?

4

17 回答 17

291

Dave Van den Eynde 的回答现在已经过时了。有 2 个重要变化,从 EF 4.1 开始,ModelBuilder 类现在是DbModelBuilder,现在有一个 DecimalPropertyConfiguration.HasPrecision 方法,其签名为:

public DecimalPropertyConfiguration HasPrecision(
byte precision,
byte scale )

其中precision是db将存储的总位数,无论小数点落在哪里,scale是它将存储的小数位数。

因此,不需要遍历所示的属性,但可以从中调用

public class EFDbContext : DbContext
{
   protected override void OnModelCreating(System.Data.Entity.DbModelBuilder modelBuilder)
   {
       modelBuilder.Entity<Class>().Property(object => object.property).HasPrecision(12, 10);

       base.OnModelCreating(modelBuilder);
   }
}
于 2011-10-14T14:30:40.717 回答
95

如果要decimals在 EF6 中设置所有精度,可以替换以下中DecimalPropertyConvention使用的默认约定DbModelBuilder

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Conventions.Remove<DecimalPropertyConvention>();
    modelBuilder.Conventions.Add(new DecimalPropertyConvention(38, 18));
}

DecimalPropertyConventionEF6 中的默认设置将decimal属性映射到decimal(18,2)列。

如果您只希望单个属性具有指定的精度,那么您可以在以下位置设置实体属性的精度DbModelBuilder

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Entity<MyEntity>().Property(e => e.Value).HasPrecision(38, 18);
}

或者,EntityTypeConfiguration<>为指定精度的实体添加一个:

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Configurations.Add(new MyEntityConfiguration());
}

internal class MyEntityConfiguration : EntityTypeConfiguration<MyEntity>
{
    internal MyEntityConfiguration()
    {
        this.Property(e => e.Value).HasPrecision(38, 18);
    }
}
于 2014-04-03T09:45:18.850 回答
81

我很高兴为此创建了一个自定义属性:

[AttributeUsage(AttributeTargets.Property, Inherited = false, AllowMultiple = false)]
public sealed class DecimalPrecisionAttribute : Attribute
{
    public DecimalPrecisionAttribute(byte precision, byte scale)
    {
        Precision = precision;
        Scale = scale;

    }

    public byte Precision { get; set; }
    public byte Scale { get; set; }

}

像这样使用它

[DecimalPrecision(20,10)]
public Nullable<decimal> DeliveryPrice { get; set; }

神奇的发生在模型创建时有一些反思

protected override void OnModelCreating(System.Data.Entity.ModelConfiguration.ModelBuilder modelBuilder)
{
    foreach (Type classType in from t in Assembly.GetAssembly(typeof(DecimalPrecisionAttribute)).GetTypes()
                                   where t.IsClass && t.Namespace == "YOURMODELNAMESPACE"
                                   select t)
     {
         foreach (var propAttr in classType.GetProperties(BindingFlags.Public | BindingFlags.Instance).Where(p => p.GetCustomAttribute<DecimalPrecisionAttribute>() != null).Select(
                p => new { prop = p, attr = p.GetCustomAttribute<DecimalPrecisionAttribute>(true) }))
         {

             var entityConfig = modelBuilder.GetType().GetMethod("Entity").MakeGenericMethod(classType).Invoke(modelBuilder, null);
             ParameterExpression param = ParameterExpression.Parameter(classType, "c");
             Expression property = Expression.Property(param, propAttr.prop.Name);
             LambdaExpression lambdaExpression = Expression.Lambda(property, true,
                                                                      new ParameterExpression[]
                                                                          {param});
             DecimalPropertyConfiguration decimalConfig;
             if (propAttr.prop.PropertyType.IsGenericType && propAttr.prop.PropertyType.GetGenericTypeDefinition() == typeof(Nullable<>))
             {
                 MethodInfo methodInfo = entityConfig.GetType().GetMethods().Where(p => p.Name == "Property").ToList()[7];
                 decimalConfig = methodInfo.Invoke(entityConfig, new[] { lambdaExpression }) as DecimalPropertyConfiguration;
             }
             else
             {
                 MethodInfo methodInfo = entityConfig.GetType().GetMethods().Where(p => p.Name == "Property").ToList()[6];
                 decimalConfig = methodInfo.Invoke(entityConfig, new[] { lambdaExpression }) as DecimalPropertyConfiguration;
             }

             decimalConfig.HasPrecision(propAttr.attr.Precision, propAttr.attr.Scale);
        }
    }
}

第一部分是获取模型中的所有类(我的自定义属性是在该程序集中定义的,所以我用它来获取模型的程序集)

第二个 foreach 使用自定义属性获取该类中的所有属性,以及属性本身,因此我可以获得精度和比例数据

之后我必须打电话

modelBuilder.Entity<MODEL_CLASS>().Property(c=> c.PROPERTY_NAME).HasPrecision(PRECISION,SCALE);

所以我通过反射调用 modelBuilder.Entity() 并将其存储在 entityConfig 变量中,然后我构建“c => c.PROPERTY_NAME” lambda 表达式

之后,如果小数可以为空,我调用

Property(Expression<Func<TStructuralType, decimal?>> propertyExpression) 

方法(我通过数组中的位置调用它,我知道这并不理想,任何帮助将不胜感激)

如果它不可为空,我会调用

Property(Expression<Func<TStructuralType, decimal>> propertyExpression)

方法。

拥有 DecimalPropertyConfiguration 我调用 HasPrecision 方法。

于 2013-03-13T13:36:03.023 回答
53

使用DecimalPrecisonAttribute来自 KinSlayerUY 的方法,在 EF6 中,您可以创建一个约定来处理具有该属性的单个属性(而不是DecimalPropertyConvention此答案中设置会影响所有十进制属性的类似属性)。

[AttributeUsage(AttributeTargets.Property, Inherited = false, AllowMultiple = false)]
public sealed class DecimalPrecisionAttribute : Attribute
{
    public DecimalPrecisionAttribute(byte precision, byte scale)
    {
        Precision = precision;
        Scale = scale;
    }
    public byte Precision { get; set; }
    public byte Scale { get; set; }
}

public class DecimalPrecisionAttributeConvention
    : PrimitivePropertyAttributeConfigurationConvention<DecimalPrecisionAttribute>
{
    public override void Apply(ConventionPrimitivePropertyConfiguration configuration, DecimalPrecisionAttribute attribute)
    {
        if (attribute.Precision < 1 || attribute.Precision > 38)
        {
            throw new InvalidOperationException("Precision must be between 1 and 38.");
        }

        if (attribute.Scale > attribute.Precision)
        {
            throw new InvalidOperationException("Scale must be between 0 and the Precision value.");
        }

        configuration.HasPrecision(attribute.Precision, attribute.Scale);
    }
}

然后在你的DbContext

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Conventions.Add(new DecimalPrecisionAttributeConvention());
}
于 2014-04-03T07:56:08.907 回答
48

Apparently, you can override the DbContext.OnModelCreating() method and configure the precision like this:

protected override void OnModelCreating(System.Data.Entity.ModelConfiguration.ModelBuilder modelBuilder)
{
    modelBuilder.Entity<Product>().Property(product => product.Price).Precision = 10;
    modelBuilder.Entity<Product>().Property(product => product.Price).Scale = 2;
}

But this is pretty tedious code when you have to do it with all your price-related properties, so I came up with this:

    protected override void OnModelCreating(System.Data.Entity.ModelConfiguration.ModelBuilder modelBuilder)
    {
        var properties = new[]
        {
            modelBuilder.Entity<Product>().Property(product => product.Price),
            modelBuilder.Entity<Order>().Property(order => order.OrderTotal),
            modelBuilder.Entity<OrderDetail>().Property(detail => detail.Total),
            modelBuilder.Entity<Option>().Property(option => option.Price)
        };

        properties.ToList().ForEach(property =>
        {
            property.Precision = 10;
            property.Scale = 2;
        });

        base.OnModelCreating(modelBuilder);
    }

It's good practice that you call the base method when you override a method, even though the base implementation does nothing.

Update: This article was also very helpful.

于 2010-08-17T16:39:25.267 回答
36
[Column(TypeName = "decimal(18,2)")]

这将与此处所述的 EF Core 代码优先迁移一起使用。

于 2018-07-18T04:33:00.770 回答
32

Entity Framework Ver 6 (Alpha, rc1) 有一个叫做Custom Conventions的东西。要设置小数精度:

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    modelBuilder.Properties<decimal>().Configure(config => config.HasPrecision(18, 4));
}

参考:

于 2013-09-18T14:33:13.520 回答
15

此代码行可能是完成相同操作的更简单方法:

 public class ProductConfiguration : EntityTypeConfiguration<Product>
    {
        public ProductConfiguration()
        {
            this.Property(m => m.Price).HasPrecision(10, 2);
        }
    }
于 2011-10-13T01:52:27.833 回答
15

- FOR EF CORE - 使用System.ComponentModel.DataAnnotations;

使用 [ColumnTypeName = "decimal精度比例")]

精度=使用的字符总数

比例=点后的总数。(容易混淆)

示例

public class Blog
{
    public int BlogId { get; set; }
    [Column(TypeName = "varchar(200)")]
    public string Url { get; set; }
    [Column(TypeName = "decimal(5, 2)")]
    public decimal Rating { get; set; }
}

更多详细信息:https ://docs.microsoft.com/en-us/ef/core/modeling/relational/data-types

于 2018-09-13T17:32:53.310 回答
5

从 .NET EF Core 6 开始,您可以使用 Precision 属性。

    [Precision(18, 2)]
    public decimal Price { get; set; }

确保您需要安装 EF Core 6 并执行以下using操作

using Microsoft.EntityFrameworkCore;
于 2021-11-22T16:52:51.610 回答
4

您始终可以通过 OnModelCreating 函数的 Context 类中的约定告诉 EF 执行此操作,如下所示:

protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
    // <... other configurations ...>
    // modelBuilder.Conventions.Remove<PluralizingTableNameConvention>();
    // modelBuilder.Conventions.Remove<ManyToManyCascadeDeleteConvention>();
    // modelBuilder.Conventions.Remove<OneToManyCascadeDeleteConvention>();

    // Configure Decimal to always have a precision of 18 and a scale of 4
    modelBuilder.Conventions.Remove<DecimalPropertyConvention>();
    modelBuilder.Conventions.Add(new DecimalPropertyConvention(18, 4));

    base.OnModelCreating(modelBuilder);
}

这仅适用于 Code First EF 仅供参考,并适用于映射到 db 的所有十进制类型。

于 2016-08-24T11:42:04.933 回答
3

在 EF6 中

modelBuilder.Properties()
    .Where(x => x.GetCustomAttributes(false).OfType<DecimalPrecisionAttribute>().Any())
    .Configure(c => {
        var attr = (DecimalPrecisionAttribute)c.ClrPropertyInfo.GetCustomAttributes(typeof (DecimalPrecisionAttribute), true).FirstOrDefault();

        c.HasPrecision(attr.Precision, attr.Scale);
    });
于 2014-02-20T13:22:08.537 回答
3

使用

System.ComponentModel.DataAnnotations;

您可以简单地将该属性放入您的模型中:

[DataType("decimal(18,5)")]
于 2017-03-09T21:22:20.600 回答
1

您可以在 MSDN - 实体数据模型方面找到更多信息。 http://msdn.microsoft.com/en-us/library/ee382834.aspx 完全推荐。

于 2011-06-09T16:57:39.827 回答
1

EntityFrameworkCore 3.1.3 的实际情况:

OnModelCreating 中的一些解决方案:

var fixDecimalDatas = new List<Tuple<Type, Type, string>>();
foreach (var entityType in builder.Model.GetEntityTypes())
{
    foreach (var property in entityType.GetProperties())
    {
        if (Type.GetTypeCode(property.ClrType) == TypeCode.Decimal)
        {
            fixDecimalDatas.Add(new Tuple<Type, Type, string>(entityType.ClrType, property.ClrType, property.GetColumnName()));
        }
    }
}

foreach (var item in fixDecimalDatas)
{
    builder.Entity(item.Item1).Property(item.Item2, item.Item3).HasColumnType("decimal(18,4)");
}

//custom decimal nullable:
builder.Entity<SomePerfectEntity>().Property(x => x.IsBeautiful).HasColumnType("decimal(18,4)");
于 2020-04-20T17:50:35.760 回答
0

@Mark007,我已将类型选择标准更改为使用 DbContext 的 DbSet<> 属性。我认为这更安全,因为有时您在给定名称空间中的类不应该是模型定义的一部分,或者它们是但不是实体。或者您的实体可以驻留在单独的名称空间或单独的程序集中,并被拉到一个上下文中。

此外,即使不太可能,我认为依赖方法定义的顺序是不安全的,所以最好通过参数列表将它们拉出来。(.GetTypeMethods() 是我为使用新的 TypeInfo 范例而构建的扩展方法,并且可以在查找方法时展平类层次结构)。

请注意 OnModelCreating 代表此方法:

    private void OnModelCreatingSetDecimalPrecisionFromAttribute(DbModelBuilder modelBuilder)
    {
        foreach (var iSetProp in this.GetType().GetTypeProperties(true))
        {
            if (iSetProp.PropertyType.IsGenericType
                    && (iSetProp.PropertyType.GetGenericTypeDefinition() == typeof(IDbSet<>) || iSetProp.PropertyType.GetGenericTypeDefinition() == typeof(DbSet<>)))
            {
                var entityType = iSetProp.PropertyType.GetGenericArguments()[0];

                foreach (var propAttr in entityType
                                        .GetProperties(BindingFlags.Public | BindingFlags.Instance)
                                        .Select(p => new { prop = p, attr = p.GetCustomAttribute<DecimalPrecisionAttribute>(true) })
                                        .Where(propAttr => propAttr.attr != null))
                {
                    var entityTypeConfigMethod = modelBuilder.GetType().GetTypeInfo().DeclaredMethods.First(m => m.Name == "Entity");
                    var entityTypeConfig = entityTypeConfigMethod.MakeGenericMethod(entityType).Invoke(modelBuilder, null);

                    var param = ParameterExpression.Parameter(entityType, "c");
                    var lambdaExpression = Expression.Lambda(Expression.Property(param, propAttr.prop.Name), true, new ParameterExpression[] { param });

                    var propertyConfigMethod =
                        entityTypeConfig.GetType()
                            .GetTypeMethods(true, false)
                            .First(m =>
                            {
                                if (m.Name != "Property")
                                    return false;

                                var methodParams = m.GetParameters();

                                return methodParams.Length == 1 && methodParams[0].ParameterType == lambdaExpression.GetType();
                            }
                            );

                    var decimalConfig = propertyConfigMethod.Invoke(entityTypeConfig, new[] { lambdaExpression }) as DecimalPropertyConfiguration;

                    decimalConfig.HasPrecision(propAttr.attr.Precision, propAttr.attr.Scale);
                }
            }
        }
    }



    public static IEnumerable<MethodInfo> GetTypeMethods(this Type typeToQuery, bool flattenHierarchy, bool? staticMembers)
    {
        var typeInfo = typeToQuery.GetTypeInfo();

        foreach (var iField in typeInfo.DeclaredMethods.Where(fi => staticMembers == null || fi.IsStatic == staticMembers))
            yield return iField;

        //this bit is just for StaticFields so we pass flag to flattenHierarchy and for the purpose of recursion, restrictStatic = false
        if (flattenHierarchy == true)
        {
            var baseType = typeInfo.BaseType;

            if ((baseType != null) && (baseType != typeof(object)))
            {
                foreach (var iField in baseType.GetTypeMethods(true, staticMembers))
                    yield return iField;
            }
        }
    }
于 2014-10-23T13:11:50.963 回答
0

KinSlayerUY 的自定义属性对我来说效果很好,但我遇到了 ComplexTypes 的问题。它们被映射为属性代码中的实体,因此无法映射为 ComplexType。

因此,我扩展了代码以允许这样做:

public static void OnModelCreating(DbModelBuilder modelBuilder)
    {
        foreach (Type classType in from t in Assembly.GetAssembly(typeof(DecimalPrecisionAttribute)).GetTypes()
                                   where t.IsClass && t.Namespace == "FA.f1rstval.Data"
                                   select t)
        {
            foreach (var propAttr in classType.GetProperties(BindingFlags.Public | BindingFlags.Instance).Where(p => p.GetCustomAttribute<DecimalPrecisionAttribute>() != null).Select(
                   p => new { prop = p, attr = p.GetCustomAttribute<DecimalPrecisionAttribute>(true) }))
            {

                ParameterExpression param = ParameterExpression.Parameter(classType, "c");
                Expression property = Expression.Property(param, propAttr.prop.Name);
                LambdaExpression lambdaExpression = Expression.Lambda(property, true,
                                                                         new ParameterExpression[] { param });
                DecimalPropertyConfiguration decimalConfig;
                int MethodNum;
                if (propAttr.prop.PropertyType.IsGenericType && propAttr.prop.PropertyType.GetGenericTypeDefinition() == typeof(Nullable<>))
                {
                    MethodNum = 7;
                }
                else
                {
                    MethodNum = 6;
                }

                //check if complextype
                if (classType.GetCustomAttribute<ComplexTypeAttribute>() != null)
                {
                    var complexConfig = modelBuilder.GetType().GetMethod("ComplexType").MakeGenericMethod(classType).Invoke(modelBuilder, null);
                    MethodInfo methodInfo = complexConfig.GetType().GetMethods().Where(p => p.Name == "Property").ToList()[MethodNum];
                    decimalConfig = methodInfo.Invoke(complexConfig, new[] { lambdaExpression }) as DecimalPropertyConfiguration;
                }
                else
                {
                    var entityConfig = modelBuilder.GetType().GetMethod("Entity").MakeGenericMethod(classType).Invoke(modelBuilder, null);
                    MethodInfo methodInfo = entityConfig.GetType().GetMethods().Where(p => p.Name == "Property").ToList()[MethodNum];
                    decimalConfig = methodInfo.Invoke(entityConfig, new[] { lambdaExpression }) as DecimalPropertyConfiguration;
                }

                decimalConfig.HasPrecision(propAttr.attr.Precision, propAttr.attr.Scale);
            }
        }
    }
于 2014-08-11T22:11:54.213 回答