2

我需要用表中的数据填充我的事实lds_placement表。我已经选择了记录，如下所示：

fk1_account_id | fk3_job_role_id | salary | no_of_placements |  YEAR
---------------------------------------------------------------------
     10        |        3        | 165000 |        5         |  2010
     10        |        3        | 132000 |        4         |  2011
     10        |        3        | 132000 |        4         |  2012
     20        |        2        | 990000 |        3         |  2010
     20        |        2        | 132000 |        2         |  2011
     20        |        2        | 132000 |        2         |  2012

我想从名为列time_id的不同表中插入，而不是实际年份本身。time_dimyear

该time_dim表如下所示：

time_id | year
---------------
   5    | 2015
   1    | 2013
   2    | 2010
   3    | 2014
   4    | 2012
   6    | 2011

我需要插入“年”列实际上是：

year
 2
 6
 4
 2
 6
 4

请给我插入time_id而不是year在表格中的方式。这是我用来选择最顶层表格的代码。

SELECT
     fk1_account_id,
     fk3_job_role_id,
     Sum(actual_salary)                             AS salary,
     Count(1)                                       AS no_of_placements,
     MAX(EXTRACT(YEAR FROM plt_estimated_end_date)) AS year
  FROM lds_placement
 GROUP BY fk1_account_id, fk3_job_role_id, EXTRACT(YEAR FROM plt_estimated_end_date)
 ORDER BY fk1_account_id;
4

1 回答 1

1

left join如果要捕获 中year不存在的记录，请使用time_dim. 其他使用inner_join。 

select t.fk1_account_id,t.fk3_job_role_id,t.salary,t.no_of_placements
,d.time_id 
from 
(SELECT fk1_account_id, fk3_job_role_id, Sum(actual_salary) as salary, Count(1) as no_of_placements, MAX(EXTRACT(YEAR FROM plt_estimated_end_date)) AS YEAR 
FROM lds_placement
GROUP BY fk1_account_id, fk3_job_role_id, EXTRACT(YEAR FROM plt_estimated_end_date)
)t
left join time_dim d
on t.year=d.year
order by t.fk1_account_id
于 2016-01-27T07:44:56.893 回答