我是 nodejs 的新手,我正在尝试 append 函数。当我运行下面的代码时,在提示他之后只接受用户输入,关于最喜欢的歌手并放入一个带有歌手姓名的文件。并附加最喜欢的歌曲,似乎如果用户输入退出它应该将它附加到文件但是,它不是???同时,如果添加了对 appendFileSync(fn 的同步版本)出口的更改?
代码:
var readline = require ('readline');
var fs = require('fs');
var rl = readline.createInterface(process.stdin, process.stdout);
var singer = {
name:'',
songs: []
};
rl.question("What is your fav singer? ", function(answer) {
singer.name = answer;
//creating a file for this singer
fs.writeFileSync(singer.name+".md", `${singer.name}\n====================\n\n`);
rl.setPrompt(`What's your fav songs for ${singer.name} ?`);
rl.prompt();
rl.on('line', function(song) {
singer.songs.push(song.trim());
fs.appendFile(singer.name+".md", `* ${song.trim()} \n`);
//***** WHY IF ITS EXIT ITS NEVER APPEND IT TO THE FILE
console.log(`* ${song.trim()} \n`);
if (song.toLowerCase().trim() === 'exit') {
fs.appendFile(singer.name+".md", "Bye");
//***** WHY ITS NEVER APPEND IT TO THE FILE
rl.close();
} else {
rl.setPrompt(`what else would ${singer.name} say? ('exit'to leave)`);
rl.prompt();
}
});
});
rl.on ('close', function() {
console.log ("%s is a real person that says %j", singer.name, singer.songs);
process.exit();
});