0

如何访问通道 2 中通道 1 的方法，以便先执行 test_script1、test_script2，然后执行 test_script3、test_script4。

注意：-主要问题是当我执行suite1= unittest.TestLoader().loadTestsFromTestCase(channel1) 和suite2= unittest.TestLoader().loadTestsFromTestCase(channel2) 时，我得到两个报告表。

但相反，我希望它们合并到一个包含 channel1 和 channel2 类数据的表中。

from sikuli import *
import unittest
import HTMLTestRunner

class channel1(unittest.TestCase):
    def test_script1(self):
        assert exists("1453186120180.png")
    def test_script2(self):
         assert exists("1453186901719.png")

class channel2(unittest.TestCase):
    def test_script3(self):
        assert exists("1453186120180.png")
    def test_script4(self):
         assert exists("1453186901719.png")
    #channel2().test_script1()
#suite1 = unittest.TestLoader().loadTestsFromTestCase(_main_channel.channel1)
#ch1=channel1.test_script1()
#ch2=channel1.test_script2()
suite2= unittest.TestLoader().loadTestsFromTestCase(channel2)
#suite2 = unittest.TestLoader().loadTestsFromTestCase(obj2)
outfile = open("D:\\report.html", "wb") # path to report folder

#runner = HTMLTestRunner.HTMLTestRunner(stream=outfile, title=' Report Title', description='desc..' ).run(suite1)
runner = HTMLTestRunner.HTMLTestRunner(stream=outfile, title=' Report Title', description='desc..' ).run(suite1)
#runner = HTMLTestRunner.HTMLTestRunner(stream=outfile, title=' Report Title', description='desc..' ).run(suite2)
#runner.run(suite2)

请帮忙..

4

0 回答 0