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我从一个包含 currentDataResult 和 pastDataResult 的 api 返回一个对象数组。

[
{
    "sectionCurrentDataResult": [
        {
            "section_id": 14785,
            "subdivision_name": "Stratton Woods",
        },
        {
            "section_id": 14790,
            "subdivision_name": "Stratton Woods",
        },
        {
            "section_id": 14791,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14792,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14781,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14786,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14787,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14788,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14782,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14783,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14784,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 5326,
            "subdivision_id": 1439,
            "subdivision_name": "Stratton Woods"
        }
    ]
},
{
    "sectionPastDataResult": [
        {
            "section_id": 5326,
            "price_min": 177,
            "price_max": 235
        },
        {
            "section_id": 14785,
            "price_min": 190,
            "price_max": 220
        },
        {
            "section_id": 14786,
            "price_min": 238,
            "price_max": 292
        },
        {
            "section_id": 14788,
            "price_min": 186,
            "price_max": 205
        },
        {
            "section_id": 14790,
            "price_min": 150,
            "price_max": 269
        },
        {
            "section_id": 14783,
            "price_min": 150,
            "price_max": 260
        },
        {
            "section_id": 14787,
            "price_min": 90,
            "price_max": 90
        },
        {
            "section_id": 14792,
            "price_min": 177,
            "price_max": 235
        },
        {
            "section_id": 14791,
            "price_min": 145,
            "price_max": 221
        },
        {
            "section_id": 14784,
            "price_min": 148,
            "price_max": 186
        },
        {
            "section_id": 14781,
            "price_min": 155,
            "price_max": 200
        },
        {
            "section_id": 14782,
            "price_min": 150,
            "price_max": 170
        }
      ]
    }
  ]

我需要将匹配的 pastDataObject(by section_id) 对象作为嵌套数组推送到 currentDataResult 对象中。这就是它需要的样子

"sectionCurrentDataResult": [
        {
            "section_id": 14785,
            "subdivision_name": "Stratton Woods",
            "sectionHistory":[{
               "section_id": 14785,
               "price_min": 190,
               "price_max": 220
            }]
        },
        {
            "section_id": 14790,
            "subdivision_name": "Stratton Woods",
            "sectionHistory":[{
               "section_id": 14790,
               "price_min": 150,
               "price_max": 269
            }]
        },
        etc....
        ]

我创建了一个服务，它同时获取当前和过去的数据结果，并重新排序过去的数据结果以匹配当前。我需要帮助的是将过去的数据数组推入当前的数据对象。现在它错误地将整个过去的数据数组推入当前数据数组的第一个对象中。我已经用我的代码设置了一个 plunker。

笨蛋

app.controller('MainCtrl', function($scope,bigEnchilada,inputHistorySvc) {

   for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i++) {
        bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory =  inputHistorySvc.historyInputs(bigEnchilada);
        }
      $scope.sections = bigEnchilada[0].sectionCurrentDataResult;

    });
4

4 回答 4

2

这是你要找的吗？

var app = angular.module('angularjs-starter', []);

app.controller('MainCtrl', function($scope,bigEnchilada,inputHistorySvc) {
var list = inputHistorySvc.historyInputs(bigEnchilada);
for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i++){
   for (var j = 0; j < list.length; j++ ) {
      if(bigEnchilada[0].sectionCurrentDataResult[i].section_id ==      list[j].section_id){
          bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory = list[j];
      }
   }
}
  $scope.sections = bigEnchilada[0].sectionCurrentDataResult;

});

输出：

[
{
"section_id": 14785,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14785,
  "price_min": 190,
  "price_max": 220
}
},
{
"section_id": 14790,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14790,
  "price_min": 150,
  "price_max": 269
}
},
 {
"section_id": 14791,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14791,
  "price_min": 145,
  "price_max": 221
}
},

等等

于 2016-01-15T14:19:38.747 回答
1 
var inputHistory = inputHistorySvc.historyInputs(bigEnchilada);
  for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i = i + 1) {
      for (x = 0; x < inputHistory.length; x = x + 1) {
        if (bigEnchilada[0].sectionCurrentDataResult[i].section_id === inputHistory[x].section_id) {
          bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory = inputHistory[x];
        }
      }
      }
  $scope.sections = bigEnchilada[0].sectionCurrentDataResult;
于 2016-01-15T14:31:24.277 回答
1

您可以使用一个临时对象和两个单独的循环。一个用于获取所有引用，第二个用于将数据分配给引用。此解决方案中的大 O ： O(n)。

var data = [{ "sectionCurrentDataResult": [{ "section_id": 14785, "subdivision_name": "Stratton Woods", }, { "section_id": 14790, "subdivision_name": "Stratton Woods", }, { "section_id": 14791, "subdivision_name": "Stratton Woods" }, { "section_id": 14792, "subdivision_name": "Stratton Woods" }, { "section_id": 14781, "subdivision_name": "Stratton Woods" }, { "section_id": 14786, "subdivision_name": "Stratton Woods" }, { "section_id": 14787, "subdivision_name": "Stratton Woods" }, { "section_id": 14788, "subdivision_name": "Stratton Woods" }, { "section_id": 14782, "subdivision_name": "Stratton Woods" }, { "section_id": 14783, "subdivision_name": "Stratton Woods" }, { "section_id": 14784, "subdivision_name": "Stratton Woods" }, { "section_id": 5326, "subdivision_id": 1439, "subdivision_name": "Stratton Woods" }] }, { "sectionPastDataResult": [{ "section_id": 5326, "price_min": 177, "price_max": 235 }, { "section_id": 14785, "price_min": 190, "price_max": 220 }, { "section_id": 14786, "price_min": 238, "price_max": 292 }, { "section_id": 14788, "price_min": 186, "price_max": 205 }, { "section_id": 14790, "price_min": 150, "price_max": 269 }, { "section_id": 14783, "price_min": 150, "price_max": 260 }, { "section_id": 14787, "price_min": 90, "price_max": 90 }, { "section_id": 14792, "price_min": 177, "price_max": 235 }, { "section_id": 14791, "price_min": 145, "price_max": 221 }, { "section_id": 14784, "price_min": 148, "price_max": 186 }, { "section_id": 14781, "price_min": 155, "price_max": 200 }, { "section_id": 14782, "price_min": 150, "price_max": 170 }] }];

void function () {
    var o = {};
    data[0].sectionCurrentDataResult.forEach(function (a) {
        o[a.section_id] = a;
    });
    data[1].sectionPastDataResult.forEach(function (a) {
        o[a.section_id].sectionHistory = [a];
    });
}();

document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>');

于 2016-01-15T14:35:51.283 回答
1

如果你打破这个 json ，你实际上可以避免嵌套循环，按 section_id 对它们进行排序，然后在一个循环中创建所需的对象。您还可以避免if -else循环和equality check 

     // Get sorted array of  sectionCurrentDataResult
var array1 = a[0]["sectionCurrentDataResult"].sort(function(x,y){
     return x.section_id>y.section_id? 1 : x.section_id<y.section_id? -1 :0; 
  })

 // Get sorted array of  sectionPastDataResult

var array2= a[1]["sectionPastDataResult"].sort(function(x,y){
     return x.section_id>y.section_id? 1 : x.section_id<y.section_id? -1 :0; 
  })

// Will be populated with merged data
var sectionCurrentDataResult=[]

  for(var a = 0;a<array1.length;a++){
      var sectionHistory=[];
      sectionHistory.push({
      "section_id":array2[a].section_id,
      "price_min":array2[a].price_min,
      "price_max":array2[a].price_max
      })
      sectionCurrentDataResult.push({
      "section_id":array1[a].section_id,
      "subdivision_name":array1[a].subdivision_name,
      "sectionHistory":sectionHistory
      })
  }
  console.log(sectionCurrentDataResult);

工作示例

于 2016-01-15T15:22:30.173 回答