c++ - 带有 set_intersection 的“向量迭代器不可递增”运行时错误

Question

为什么此代码会导致运行时错误“向量迭代器不可递增”？

vector<string> s1, s2;

 s1.push_back("joe");
 s1.push_back("steve");
 s1.push_back("jill");
 s1.push_back("svetlana");

 s2.push_back("bob");
 s2.push_back("james");
 s2.push_back("jill");
 s2.push_back("barbara");
 s2.push_back("steve");

 sort(s1.begin(), s1.end());
 sort(s2.begin(), s2.end());

 vector<string> result;
 vector<string>::iterator it_end, it_begin;
 it_end = set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(), result.begin());
 cout << int (it_end - result.begin()) << endl;
 for_each(result.begin(), result.end(), print);

Answer 1

result.begin()空向量不是有效的输出迭代器。你需要一个代替。 back_inserter(result)

#include <iterator>
...
set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(), back_inserter(result));
cout << result.size() << endl;

或者，将大小调整result为至少 4，以便向量可以包含所有结果。