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是否可以在每个日志行中显示传递给“syslog”函数的级别(LOG_INFO、LOG_ERROR、...)信息?

谢谢!安东尼奥

4

2 回答 2

1

只需为您的目标文件使用一个模板,您可以在其中指定您的日志消息将如何显示/写入;像这样的东西只显示系统日志级别和消息:

template t_example { template("${LEVEL}" "${MSG}"); };

destination d_example { file("/var/log/example.log" template(t_example) ); };
于 2016-10-21T09:20:14.327 回答
1

你可以写一个这样的包装函数

#include <stdarg.h>
#include <stdio.h>
#include <syslog.h>
#include <string.h>
#include <stdlib.h>

int
mysyslog(int __level, const char *const syslogformat, ...)
{
    va_list args;
    char *format;
    size_t length;
    char *level;
    ssize_t result;

    va_start(args,syslogformat);

    level = "?";
    switch (__level)
    {
        case LOG_ALERT:
            level = "LOG_ALERT";
            break;
        case LOG_INFO:
            level = "LOG_INFO";
            break;
       case LOG_EMERG:
            level = "LOG_EMERG";
            break;
       case LOG_CRIT:
            level = "LOG_CRIT";
            break;
       case LOG_ERR:
            level = "LOG_ERR";
            break;
       case LOG_WARNING:
            level = "LOG_WARNING";
            break;
       case LOG_NOTICE:
            level = "LOG_NOTICE";
            break;
       case LOG_DEBUG:
            level = "LOG_DEBUG";
            break;
    }

    length = strlen(syslogformat) + strlen(level) + 2;
    format = malloc(length + 1);
    result = snprintf(format, length + 1, "%s: %s", level, syslogformat);
    if ((result < 0) || (result >= length + 1))
        return -1;
    vsyslog(__level, format, args);
    va_end(args);

    return 0;
}

int main(void) 
{
    mysyslog(LOG_NOTICE, "This is a log message `%d' with an integer as parameter\n", 100);
    return 0;
}
于 2016-01-13T22:57:47.250 回答