14

我正在为一个项目的 Blender 编写 Python 脚本,但我对这门语言还很陌生。我感到困惑的是静态变量的使用。这是我目前正在处理的一段代码:

class panelToggle(bpy.types.Operator):
    active = False

    def invoke(self, context, event):
        self.active = not self.active
        return{'FINISHED'}

class OBJECT_OT_openConstraintPanel(panelToggle):
    bl_label = "openConstraintPanel"
    bl_idname = "openConstraintPanel"

这个想法是第二个类应该从第一个类继承活动变量和调用方法,以便调用 OBJECT_OT_openConstraintPanel.invoke() 更改 OBJECT_OT_openConstraintPanel.active。然而,像我上面那样使用self是行不通的,使用panelToggle也行不通。知道我该怎么做吗?

4

2 回答 2

22

用于type(self)访问类属性

>>> class A(object):
 var  = 2
 def write(self):
  print type(self).var
>>> class B(A):
 pass
>>> B().write()
2
>>> B.var = 3
>>> B().write()
3
>>> A().write()
2
于 2010-08-13T09:44:22.423 回答
4

您可以active通过它所属的类访问:

if panelToggle.active:
    # do something

如果要从方法访问变量,可以编写:

def am_i_active(self):
    """ This method will access the right *class* variable by
        looking at its own class type first.
    """
    if self.__class__.active:
        print 'Yes, sir!'
    else:
        print 'Nope.'

可以在这里找到一个工作示例:http: //gist.github.com/522619


self变量(self按约定命名)是类的当前实例,隐式传递但显式接收。

class A(object):

    answer = 42

    def add(self, a, b):
        """ ``self`` is received explicitely. """
        return A.answer + a + b

a = A()

print a.add(1, 2) # ``The instance -- ``a`` -- is passed implicitely.``
# => 45

print a.answer 
# => print 42
于 2010-08-13T09:23:52.143 回答