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我正在paginate尝试Flask使用Peewee. 我正在尝试使用来自.playhouse.flask_utils

你可以看到这个例子object_list看起来很简单，下面的代码是我想要做的：

from flask import Flask
from playhouse.flask_utils import object_list
from peewee import *
from database import *

@app.route("/items/")                                                         
def items():                                                                  
    all_items = Quote.select()                                                     
    return object_list("items.html", all_items)

该模板items.html包含以下内容：

<p>Hello world</p>                                               
{% for item in all_items %}                                                       
    <p>{{ item.text }}</p>                                                    
{% endfor %}                                                                    

{% if page > 1 %}                                                               
    <a class="previous" href="./?page={{ page - 1 }}">Previous</a>              
{% endif %}                                                                     
{% if pagination.get_pages() > page %}                                          
    <a class="next" href="./?page={{ page + 1 }}">Next</a>                      
{% endif %}

当然，我运行python app.py但收到500 内部服务器错误。我有兴趣对查询结果进行分页，知道如何实现这一点吗？或者你能发现我在这里做错了什么吗？先感谢您。

编辑#1，终端出现以下错误：

127.0.0.1 - - [09/Jan/2016 20:47:17] "GET /items/ HTTP/1.1" 500 -
Traceback (most recent call last):
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/web/index.py", line 19, in items
    return object_list("items.html", all_items)
  File "/usr/lib/python2.7/site-packages/playhouse/flask_utils.py", line 64, in object_list
    **kwargs)
  File "/usr/lib/python2.7/site-packages/flask/templating.py", line 128, in render_template
    context, ctx.app)
  File "/usr/lib/python2.7/site-packages/flask/templating.py", line 110, in _render
    rv = template.render(context)
  File "/usr/lib/python2.7/site-packages/jinja2/environment.py", line 989, in render
    return self.environment.handle_exception(exc_info, True)
  File "/usr/lib/python2.7/site-packages/jinja2/environment.py", line 754, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/web/templates/items.html", line 9, in top-level template code
    {% if pagination.get_pages() > page %}
UndefinedError: 'playhouse.flask_utils.PaginatedQuery object' has no attribute 'get_pages'
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1 回答 1

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没有get_pages()办法。用途：get_page(x)获取一页结果。用于get_page_count()获取总页数。

这都记录在这里：http ://docs.peewee-orm.com/en/latest/peewee/playhouse.html#PaginatedQuery

于 2016-01-13T17:43:49.870 回答