android - 如何在android中发送HttpRequest并获取Json响应？

Question

我想使用wp-api插件为我的 wordpress 网站构建一个 android 应用程序。我如何发送 HttpRequest(GET) 并在 Json 中接收响应？

Answer 1

使用此函数从 URL 获取 JSON。

public static JSONObject getJSONObjectFromURL(String urlString) throws IOException, JSONException {
    HttpURLConnection urlConnection = null;
    URL url = new URL(urlString);
    urlConnection = (HttpURLConnection) url.openConnection();
    urlConnection.setRequestMethod("GET");
    urlConnection.setReadTimeout(10000 /* milliseconds */ );
    urlConnection.setConnectTimeout(15000 /* milliseconds */ );
    urlConnection.setDoOutput(true);
    urlConnection.connect();

    BufferedReader br = new BufferedReader(new InputStreamReader(url.openStream()));
    StringBuilder sb = new StringBuilder();

    String line;
    while ((line = br.readLine()) != null) {
        sb.append(line + "\n");
    }
    br.close();

    String jsonString = sb.toString();
    System.out.println("JSON: " + jsonString);

    return new JSONObject(jsonString);
}

不要忘记在清单中添加 Internet 权限

<uses-permission android:name="android.permission.INTERNET" />

然后像这样使用它：

try{
      JSONObject jsonObject = getJSONObjectFromURL(urlString);
      //
      // Parse your json here
      //
} catch (IOException e) {
      e.printStackTrace();
} catch (JSONException e) {
      e.printStackTrace();
}

Answer 2

尝试以下代码从 URL 获取 json

HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget= new HttpGet(URL);

HttpResponse response = httpclient.execute(httpget);

if(response.getStatusLine().getStatusCode()==200){
   String server_response = EntityUtils.toString(response.getEntity());
   Log.i("Server response", server_response );
} else {
   Log.i("Server response", "Failed to get server response" );
}

Answer 3

try {
            String line, newjson = "";
            URL urls = new URL(url);
            try (BufferedReader reader = new BufferedReader(new InputStreamReader(urls.openStream(), "UTF-8"))) {
                while ((line = reader.readLine()) != null) {
                    newjson += line;
                    // System.out.println(line);
                }
                // System.out.println(newjson);
                String json = newjson.toString();
               JSONObject jObj = new JSONObject(json);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }