r - 输出子图节点的名称/ID列表（子同构）

Question

我想计算完整的 3 节点子图的数量。原始图的节点具有名称。示例代码如下。

g <- graph.full(n=5, directed = TRUE)

# adjacency matrices 
d3<-matrix(c(0,1,1,1,0,1,1,1,0),nrow=3,ncol=3)

# Turn them into a convenient list
sbgDouble.mat<-list(d3)

# And then into a list of graph objects
sbgDouble.graph<-lapply(sbgDouble.mat, graph.adjacency)

# Count the number of the full 3-node subgraph

subgraph.freq.g<-c()

subgraph.freq.g[1]<-
graph.count.subisomorphisms.vf2(g, sbgDouble.graph[[1]])

#> subgraph.freq.g
# [1]  60

更新：我试过graph.get.isomorphisms.vf2(g, sbgDouble.graph[[1]])但结果是list().

有人可以告诉我如何输出 3 节点子图的节点名称/ID 列表吗？谢谢。

Answer 1

为了查看顶点 ID，我们可以使用函数graph.get.subisomorphisms.vf2()，例如，

graph.get.subisomorphisms.vf2(g, sbgDouble.graph[[1]])[1]
[[1]]
+ 3/5 vertices:
[1] 1 2 3