matlab - 图例位置“最佳”，但尽可能在角落

Question

我想将我的图例的位置设置为“最佳”（如legend('y1','y2','Location','Best')），这样图例就不会与我的线条发生冲突，但同时，如果可能的话，我希望将它放在一个角落里，而不会发生数据冲突。有没有办法实现这一点？

Answer 1

如果有人对此感兴趣，我编写了一个基于@S.. 的函数，它确实是我想要实现的。这是代码：

function setPositionCornerBest( figureHandle )
%Sets the Location of the legend of the figure that is referenced by figureHandle to one of the Corners if there is no data in the Corners. Otherwise it sets it to 'Best'
h = figureHandle;

figObjects = get(h,'Children');
legHandle = findobj(figObjects,'Tag','legend');
axHandle = findobj(figObjects,'Type','axes','-and','Tag','');
lineHandle = findobj(figObjects,'Type','line','-and','Parent',axHandle);
axPos = get(axHandle,'Position');

LimX = get(axHandle,'XLim');
LimY = get(axHandle,'YLim');

xScaling = (LimX(2)-LimX(1))/axPos(3);
yScaling = (LimY(2)-LimY(1))/axPos(4);

locCell = {'NorthWest','NorthEast','SouthEast','SouthWest'};
ii = 1;
interSecFlag = true;

while (interSecFlag) && (ii<=4)
    set(legHandle,'Location',locCell{ii});
    legPos = get(legHandle,'Position');

    x(1) = LimX(1)+(legPos(1)-axPos(1))*xScaling;
    x(2) = x(1);
    x(3) = LimX(1)+(legPos(1)+legPos(3)-axPos(1))*xScaling;
    x(4) = x(3);
    x(5) = x(1);

    y(1) = LimY(1)+(legPos(2)-axPos(2))*yScaling;
    y(2) = LimY(1)+(legPos(2)+legPos(4)-axPos(2))*yScaling;
    y(3) = y(2);
    y(4) = y(1);
    y(5) = y(1);

    for jj = 1:numel(lineHandle)
        xline = get(lineHandle(jj),'XData');
        yline = get(lineHandle(jj),'YData');
        [xInter ~] = intersections(x,y,xline,yline);
        if numel(xInter) == 0
            xInterFlag(jj) = 0;
        else
            xInterFlag(jj) = 1;
        end
    end

    if all(xInterFlag==0)
        interSecFlag = false;
    end

    ii = ii + 1;
end

if interSecFlag
    set(legHandle,'Location','Best');
end

end

Answer 2

我没有完整的答案，只有草图。但是，您可以尝试先将图例设置在角落

a=legend('y1', 'y2', 'Location', 'NorthEast')

然后获取它的位置

get(a,'Position')

您可以将此位置转换为坐标，并使用http://www.mathworks.com/matlabcentral/fileexchange/11837-fast-and-robust-curve-intersections简单地测试您的线条是否跨越图例的任何边界 。如果这是情况下，再试一个角，直到没有角为止。在这种情况下，请使用“最佳”。