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我试图从存储在 PROGMEM 中的结构中读取函数指针,然后将值(输入)传递给相应的函数并保存返回值,但我找不到正确的语法。

uint8_t (*pStateFunc) (uint8_t);
uint8_t input; 
uint8_t nextstate;

enum MENUSTATES {STATE1, STATE2};

typedef struct PROGMEM {
  unsigned char state;
  uint16_t someNumber;   // Just arbitrary information
  uint8_t (*pFunc) (uint8_t input);
} MENU_STATE;

const MENU_STATE menu_state[] PROGMEM = {
  //  state  someNumber  pFunc
  {STATE1,   2,          NULL}, 
  {STATE2,   4,          doSomething},
  {0,        0,          NULL}
  };


// Get the Function 
pStateFunc = (PGM_VOID_P) pgm_read_byte(&menu_state[1].pFunc); 

// Execute the Function and save the returned state
nextstate = pStateFunc(input);

// Function Definition
uint8_t doSomething(u8int_t input){
    return STATE1;
}

我得到的只是来自 Arduino IDE 1.6.5 的以下错误:

invalid conversion from 'const void*' to 'uint8_t (*)(uint8_t) {aka unsigned char (*)(unsigned char)}' [-fpermissive]

如何从 PROGMEM 读取函数并正确执行?

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1 回答 1

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您似乎正在读取一个字节-我认为pgm_read_ptr会更合适。您需要将其转换为正确的类型:

typedef uint8_t (*StateFunc) (uint8_t);
pStateFunc = (StateFunc) pgm_read_ptr(&menu_state[1].pFunc); 
于 2016-01-03T13:53:29.393 回答