19

国家代码有几种方法。

我有一个包含 3 个字符的代码列表,例如在此页面上:

http://www.fina.org/H2O/index.php?option=com_content&view=category&id=93:asia&Itemid=638&layout=default

有没有一种简单的方法可以将它们转换为 2 个字符?就像葡萄牙的“POR”中的“PT”。

2 个字符的标准 - http://en.wikipedia.org/wiki/ISO_3166-1_alpha-2

谢谢。

4

12 回答 12

33

您可以从http://country.io/data获得一些有用的数据文件,这些文件将对您有所帮助:

如果您只想从 3 个字母代码变为 2 个字母代码,您可以翻转第一张地图并使用它。您可以通过组合文件来创建一个直接从 3 个字母代码到国家名称的地图。这是一个简单的 PHP 示例:

$codes = json_decode(file_get_contents('http://country.io/iso3.json'), true);
$names = json_decode(file_get_contents('http://country.io/names.json'), true);
$iso3_to_name = array();
foreach($codes as $iso2 => $iso3) {
    $iso3_to_name[$iso3] = $names[$iso2];
}

echo $names("PL"); // => "Poland"
echo $iso3_to_map("POL"); // => "Poland"
于 2014-09-10T20:39:49.797 回答
9

我看到这个问题是七年前提出的。今天我遇到了类似的问题,并找到了一个很好的解决方案。希望这个答案对以后遇到同样问题的其他人有所帮助。

有一个单独的库可以使用https://github.com/thephpleague/iso3166

那么解决方案将很简单。$alpha3是一个国家的三个字符表示。而alpha2是国家的两个字符表示。

  1. $ composer require league/iso3166
  2. $data = (new League\ISO3166\ISO3166)->alpha3($alpha3);
  3. 数据如下:

    [
      'name' => 'Netherlands',
      'alpha2' => 'NL',
      'alpha3' => 'NLD',
      'numeric' => '528',
      'currency' => [
        'EUR',
        ]
    ]
    
  4. $countryCodeInTwoChar = $data['alpha2']
于 2017-08-29T08:54:24.690 回答
4

如果不进行实际查找,就没有简单的方法:AFG(阿富汗)变成 AF,而 AND(安道尔)变成 AD,BLR(白俄罗斯)变成 BY……所以你不能做任何简单的字符操作来转换。

我的建议是使用国家/地区代码表,或在任何现有表中添加一个额外的列,以便您保存两个代码。

于 2010-08-11T08:27:13.483 回答
3

在此处的其他信息的基础上,这里有一个完整的功能可供使用:

function convertCountryAlphas3To2($code='') {
 $countries = json_decode('{"AFG":"AF","ALA":"AX","ALB":"AL","DZA":"DZ","ASM":"AS","AND":"AD","AGO":"AO","AIA":"AI","ATA":"AQ","ATG":"AG","ARG":"AR","ARM":"AM","ABW":"AW","AUS":"AU","AUT":"AT","AZE":"AZ","BHS":"BS","BHR":"BH","BGD":"BD","BRB":"BB","BLR":"BY","BEL":"BE","BLZ":"BZ","BEN":"BJ","BMU":"BM","BTN":"BT","BOL":"BO","BIH":"BA","BWA":"BW","BVT":"BV","BRA":"BR","VGB":"VG","IOT":"IO","BRN":"BN","BGR":"BG","BFA":"BF","BDI":"BI","KHM":"KH","CMR":"CM","CAN":"CA","CPV":"CV","CYM":"KY","CAF":"CF","TCD":"TD","CHL":"CL","CHN":"CN","HKG":"HK","MAC":"MO","CXR":"CX","CCK":"CC","COL":"CO","COM":"KM","COG":"CG","COD":"CD","COK":"CK","CRI":"CR","CIV":"CI","HRV":"HR","CUB":"CU","CYP":"CY","CZE":"CZ","DNK":"DK","DKK":"DK","DJI":"DJ","DMA":"DM","DOM":"DO","ECU":"EC","Sal":"El","GNQ":"GQ","ERI":"ER","EST":"EE","ETH":"ET","FLK":"FK","FRO":"FO","FJI":"FJ","FIN":"FI","FRA":"FR","GUF":"GF","PYF":"PF","ATF":"TF","GAB":"GA","GMB":"GM","GEO":"GE","DEU":"DE","GHA":"GH","GIB":"GI","GRC":"GR","GRL":"GL","GRD":"GD","GLP":"GP","GUM":"GU","GTM":"GT","GGY":"GG","GIN":"GN","GNB":"GW","GUY":"GY","HTI":"HT","HMD":"HM","VAT":"VA","HND":"HN","HUN":"HU","ISL":"IS","IND":"IN","IDN":"ID","IRN":"IR","IRQ":"IQ","IRL":"IE","IMN":"IM","ISR":"IL","ITA":"IT","JAM":"JM","JPN":"JP","JEY":"JE","JOR":"JO","KAZ":"KZ","KEN":"KE","KIR":"KI","PRK":"KP","KOR":"KR","KWT":"KW","KGZ":"KG","LAO":"LA","LVA":"LV","LBN":"LB","LSO":"LS","LBR":"LR","LBY":"LY","LIE":"LI","LTU":"LT","LUX":"LU","MKD":"MK","MDG":"MG","MWI":"MW","MYS":"MY","MDV":"MV","MLI":"ML","MLT":"MT","MHL":"MH","MTQ":"MQ","MRT":"MR","MUS":"MU","MYT":"YT","MEX":"MX","FSM":"FM","MDA":"MD","MCO":"MC","MNG":"MN","MNE":"ME","MSR":"MS","MAR":"MA","MOZ":"MZ","MMR":"MM","NAM":"NA","NRU":"NR","NPL":"NP","NLD":"NL","ANT":"AN","NCL":"NC","NZL":"NZ","NIC":"NI","NER":"NE","NGA":"NG","NIU":"NU","NFK":"NF","MNP":"MP","NOR":"NO","OMN":"OM","PAK":"PK","PLW":"PW","PSE":"PS","PAN":"PA","PNG":"PG","PRY":"PY","PER":"PE","PHL":"PH","PCN":"PN","POL":"PL","PRT":"PT","PRI":"PR","QAT":"QA","REU":"RE","ROU":"RO","RUS":"RU","RWA":"RW","BLM":"BL","SHN":"SH","KNA":"KN","LCA":"LC","MAF":"MF","SPM":"PM","VCT":"VC","WSM":"WS","SMR":"SM","STP":"ST","SAU":"SA","SEN":"SN","SRB":"RS","SYC":"SC","SLE":"SL","SGP":"SG","SVK":"SK","SVN":"SI","SLB":"SB","SOM":"SO","ZAF":"ZA","SGS":"GS","SSD":"SS","ESP":"ES","LKA":"LK","SDN":"SD","SUR":"SR","SJM":"SJ","SWZ":"SZ","SWE":"SE","CHE":"CH","SYR":"SY","TWN":"TW","TJK":"TJ","TZA":"TZ","THA":"TH","TLS":"TL","TGO":"TG","TKL":"TK","TON":"TO","TTO":"TT","TUN":"TN","TUR":"TR","TKM":"TM","TCA":"TC","TUV":"TV","UGA":"UG","UKR":"UA","ARE":"AE","GBR":"GB","USA":"US","UMI":"UM","URY":"UY","UZB":"UZ","VUT":"VU","VEN":"VE","VNM":"VN","VIR":"VI","WLF":"WF","ESH":"EH","YEM":"YE","ZMB":"ZM","ZWE":"ZW","GBP":"GB","RUB":"RU","NOK":"NO"}',true);
 $out = $countries[$code];
 return $out;
}
于 2018-11-04T12:48:46.893 回答
2

gis.stackexchange 中有一个类似的问题。
https://gis.stackexchange.com/questions/603/is-a-country-state-city-database-available
我认为您可以通过在 gis 中发布此问题来获得更多信息。 http://gis.stackexchange.com

于 2010-08-11T08:26:36.320 回答
2

对于任何解决这个问题的人,我已经制作了一个 JSON 映射 alpha3 到 alpha2。在这里下载:https ://api.myjson.com/bins/1y2hn

因此,您只需将此 JSON 分配给一个对象(例如 countryCodes)。现在转换只是: countryCodes["US"] //"USA"

于 2016-07-27T09:41:27.927 回答
2

上面的大多数其他答案都不是直接答案。让我试试

我尝试使用以下代码将 3 个字符转换为 2 个字符的国家/地区代码,使用API

<?php
    $list=["BWA","SLV","TZA","BRB","IND","BES","ANT"];
    $iso3=file_get_contents('http://country.io/iso3.json');//load the country codes
    $iso3=json_decode($iso3,true);//convert json to associative array
    foreach($list as $k)
    {
        if($k=="ANT")//not defined in code list
            echo "AN";
        else
            echo array_search($k,$iso3); 
        echo "<br/>";
    }
?>

提供的国家代码采用 2-iso(key):3-iso(value) 的形式。因此,我没有搜索键,而是按值搜索,如果成功则返回第一个对应的键。

输出

体重

SV

太极

BB

BQ

一个

缺点 -

ANT国家代码未在代码列表中定义。

参考- array_search

于 2016-11-05T20:55:59.587 回答
1

虽然这可能是一个漫长而痛苦的方法,但在编写一个可以永久保留的函数时可能非常值得,也许这可以为您指明正确的方向:

<?php
function myCodes($in, $type){
$out = "";
$long = array('portugal', 'united kingdom');
$short = array('pt', 'uk');
$in = strtolower(trim($in));
switch($type){
case 'long':$out = str_replace($short, $long, $in);break;
case 'short':$out = str_replace($long, $short, $in);break;
}
echo $out;
}

echo myCodes('United Kingdom', 'short'); //this will echo 'uk'
echo myCodes('UK', 'long'); //this will echo 'united kingdom'

?>

这当然会有一些缺点,例如确保多头和空头的数组匹配位置明智,并且您还需要维护该功能。

于 2010-08-11T08:39:15.270 回答
1

具有 ISO 3 代码但未排序的基于 Json 的数组

粘贴 Bin 链接

和 PHP 数组 粘贴 BIN PHP 数组

于 2017-03-23T21:44:44.853 回答
0

$mapping['POR'] = 'PT';
$shortcode = $mapping[$longcode];

于 2010-08-11T08:26:47.593 回答
0

在 ruby​​ 中,您可以这样做:(从http://download.geonames.org/export/dump/获取 countryInfo.txt )

require 'csv'
countries_iso3_map = {}
CSV.foreach('countryInfo.txt',:col_sep=>'   ',:row_sep =>:auto) do |row|
   next if row[0][0] == '#' #ignore comments section
   countries_iso3_map[row[0][0,2]]= row[1][0,3]
end
p countries_iso3_map['PT']
于 2011-07-20T21:37:47.857 回答
-5

不会有简单的方法,因为国家名称中没有特定的计划。例如PTPOR对于Portugal其他国家/地区,这也可能有所不同。您可能想要创建一个数组来为每个国家/地区保存两个字母。

例子:

$countries = array('PT' => 'Portugal', 'UK' => 'United Kingdom');
于 2010-08-11T08:27:50.983 回答