LDA 2000h ; Store the no of byte that each number consists of in memory location 2000h.
MOV C A
MOV B A
LXI D 5000h
LXI H 2001h
STC
CMC
LOOP1: MOV A M
SHLD 7000h
LOOP: INX H
DCR C
JNZ LOOP
ADC M
STAX D
LHLD 7000h
LDA 2000h
MOV C A
INX D
INX H
DCR B
JNZ LOOP1
HLT
这是我解决上述问题的代码。这样做会更有效的算法是什么？