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我知道在 Oracle 中有一些字符串函数，如UPPER, LOWER, INITCAP. 但我只需要大写的句子（或短语）的第一个字母，所有其他小写字母，考虑到单词由空格或非字母数字字符分隔，句子由标点符号分隔。

所以，转换这个：

PEDIDO CANCELADO, DEVIDO AO ENCERRAMENTO DE INVESTIMENTO. SERÁ GERADA UMA NOVA REQUISIÇÃO PARA REGULARIZAR ESTA QUESTÃO.

至

Pedido cancelado, devido ao encerramento de investimento. Será gerada uma nova requisição para regularizar esta questão.

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2 回答 2

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就像只在 Oracle 10g 中引入了本机函数并支持 SQL 和 PL/SQL 中的正则表达式，我用来解决我在 plsql 中的问题的一个选项是创建一个函数：

create or replace function scase(s in varchar2) return varchar2 as
  s_len    number;  
  cur      char(2); /*char(2) for accented character */
  up       boolean;
  terminal char(10) := '.?!]';
  r        varchar2(32767);
begin

  s_len := length(trim(s));

  if s_len = 0 then
    return r;
  end if;

  r := r || UPPER(substr(s, 0, 1)); /*First character of sentence*/

  for i in 2 .. s_len loop

    cur := substr(s, i, 1);

    if up = TRUE then
      if cur = ' ' then 
        r := r || ' ';
      else
        r := r || Upper(trim(cur));
        up := FALSE;        
      end if;
    else
       if cur = ' ' then 
        r := r || ' ';
      else
        r := r || Lower(trim(cur));
      end if;
    end if;

    /*I have found a bug here(Oracle 8i): instr return 7 when is ' ' (blank space) */
    if instr(terminal, trim(cur)) between 1 and 6 then
      up := TRUE;      
    end if;
  end loop;

  return r;
exception
  when others then
    raise;
end;

另一种选择是在 java 2 中创建一个类。2000 年 8 月的最后一个版本的 Oracle 8i (8.1.7) 支持 java 2。

因此，您可以在 java 中创建代码，如下所示：

create or replace and compile java source named tosentencecase as
public class toSentenceCase
{
 public static String toSentenceCase(String s) {
       String r = "";
       if (s.length() == 0) {
           return r;
       }
       char c1 = s.charAt(0);
       r = r + Character.toUpperCase(c1);  /*First character of sentence*/

       boolean up = false;
       char[] terminal = {'.', '?', '!'};
       for (int i = 1; i < s.length(); i++) {
           char cur = s.charAt(i);
           if (up) {
               if (cur == ' ') {
                   r = r + cur;
               } else {
                   r = r +  Character.toUpperCase(cur);;
                   up = false;
               }
           } else {
               r = r +  Character.toLowerCase(cur);;
           }
           for (int j = 0; j < terminal.length; j++) {
               if (cur == terminal[j]) {
                   up = true;
                   break;
               }
           }
       }
       return r;
   }
}

在创建一个调用该代码的函数之后，如下所示：

CREATE OR REPLACE FUNCTION toSentenceCase (s IN STRING) RETURN STRING
AS LANGUAGE JAVA
NAME 'toSentenceCase.toSentenceCase (java.lang.String) return String';

之后就像普通函数一样调用：

Connected to Oracle8i Enterprise Edition Release 8.1.7.3.0 

SQL> Select toSentenceCase('PEDIDO CANCELADO, DEVIDO AO ENCERRAMENTO DE INVESTIMENTO. SERÁ GERADA UMA NOVA REQUISIÇÃO PARA REGULARIZAR ESTA QUESTÃO.')
  2    from dual;

TOSENTENCECASE('PEDIDOCANCELAD
--------------------------------------------------------------------------------
Pedido cancelado, devido ao encerramento de investimento. Será gerada uma nova r

SQL>

PS：使用 java 2（嵌入在 Oracle 8i 中）我尝试了 import java.util.regex.Matcher 和 import java.util.regex.Pattern 但无法编译代码以使用正则表达式。

于 2016-01-06T03:26:05.297 回答
0

在一个句子的情况下，以下将起作用。

with YOUR_TABLE AS 
(
  select 'THIS is a SENTENCE.' as YOUR_COLUMN from dual
)

select UPPER(SUBSTR(YOUR_COLUMN,1,1))||LOWER(SUBSTR(YOUR_COLUMN,2,LENGTH(YOUR_COLUMN))) as SENTENCE from YOUR_TABLE

SENTENCE          
-------------------
This is a sentence.

类似于在 Oracle 中将字符串拆分为多行的答案可以帮助提供一个表，其中包含文本正文中每个句子的行，可以在该表上运行该表达式。

于 2018-10-17T02:19:54.903 回答