我正在尝试有条件地显示 HTML 页面的内容,具体取决于是否为公认的公司生成了文档。
但是,转换不起作用,我不明白为什么:(我使用 MSXML3.0 作为转换器,使用 oXygen 作为 IDE,这给出了我在下面提出的错误。
我所做的是构建一长串所有公认的公司(默认和额外的,如果有的话)。然后我将它们拆分为存储在变量<token>
中的元素。$companiesKnownList
为了确定一家公司是否在该列表中,我计算了它出现的次数:
count($companiesKnownList/token[normalize-space(.) = $productName]) < 1
如果小于 1,则公司不出现在$companiesKnownList
变量中,因此无法识别。否则,如果它在$companiesKnownList
变量中出现一次或多次,则它是公认的公司。然而,这是它中断并显示以下错误的地方:
Description: Code: 0x80004005
Description: The XSL processor stack has overflowed - probable cause is infinite template recursion.
Description: The transformer process ended with code: 1
我注意到,如果我的 XML 有一家公认的公司,@ProductName="ski"
那么转换会因堆栈溢出而失败。如果我有一家未被认可的公司,@ProductName="bla"
则显示转换作品并显示它不是认可公司的文本。
我不明白合法公司出了什么问题。如果您能帮助我,我将不胜感激。我已经盯着它看了一天......没有任何进展:S
谢谢!
这是我的样式表:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:str="http://exslt.org/strings"
extension-element-prefixes="msxsl str"
version="1.0">
<!-- Taken from http://www.exslt.org/str/functions/tokenize/index.html -->
<xsl:import href="str.tokenize.template.xsl"/>
<!-- normalize and lowcase product name -->
<xsl:variable name="productName"
select="normalize-space(translate(/Doc/@ProductName, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz'))"/>
<!-- default recognised companies for all docs -->
<xsl:variable name="defaultRecognisedCompanies" select="'ski, holiday, summer trips'"/>
<!-- Determine what companies to generate a doc for -->
<xsl:variable name="companiesKnownListRaw">
<xsl:call-template name="recognisedCompanies"/>
</xsl:variable>
<xsl:variable name="companiesKnownList" select="msxsl:node-set($companiesKnownListRaw)"/>
<!-- Lists recognised companies for a document to be generated for -->
<xsl:template name="recognisedCompanies">
<xsl:call-template name="recognisedCompaniesListForDocument"/>
</xsl:template>
<xsl:template name="recognisedCompaniesListForDocument">
<xsl:param name="defaultCompanies" select="$defaultRecognisedCompanies"/>
<xsl:param name="isUseDefaultsCompanies" select="true()"/>
<xsl:param name="extraCompanies" select="''"/>
<xsl:variable name="allCompaniesRaw">
<xsl:call-template name="str:tokenize">
<xsl:with-param name="string">
<xsl:choose>
<!-- keep default companies -->
<xsl:when test="$isUseDefaultsCompanies = 'true'">
<xsl:value-of select="concat($defaultCompanies, ', ', $extraCompanies)"/>
</xsl:when>
<!-- discard default companies -->
<xsl:otherwise>
<xsl:value-of select="$extraCompanies"/>
</xsl:otherwise>
</xsl:choose>
</xsl:with-param>
<xsl:with-param name="delimiters" select="','" />
</xsl:call-template>
</xsl:variable>
<!-- Normalize token's value and discard empty values -->
<xsl:for-each select="msxsl:node-set($allCompaniesRaw)/token">
<xsl:if test="normalize-space(.) != ''">
<token>
<xsl:value-of select="normalize-space(.)"/>
</token>
</xsl:if>
</xsl:for-each>
</xsl:template>
<!-- Construct HTML doc. Display appropriate message for a company if it's recognized or not -->
<xsl:output method="html" doctype-public="-//W3C//DTD HTML 4.01 Transitional//EN"
doctype-system="http://www.w3.org/TR/html4/loose.dtd" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Doc">
<html>
<xsl:choose>
<!-- Not recognised company -->
<!-- There is something wrong with the count conditions, and I don't understand what :( -->
<xsl:when test="count($companiesKnownList/token[normalize-space(.) = $productName]) < 1">
<body>
<div align="center">
This type of company is NOT recognised for this document.
</div>
</body>
</xsl:when>
<!-- Recognised company -->
<xsl:otherwise>
<body>
<div align="center">
This type of company is recognised for this document.
</div>
</body>
</xsl:otherwise>
</xsl:choose>
</html>
</xsl:template>
</xsl:stylesheet>
XML很简单,例如:
在此示例中,ski
是公认的公司,但转换失败。
<?xml version="1.0" encoding="UTF-8"?>
<Doc ProductName="ski" />
在此示例中,bla
is not a known company 并且转换成功并显示文本:“此文档无法识别此类公司。”
<?xml version="1.0" encoding="UTF-8"?>
<Doc ProductName="bla" />