31

是否有人熟悉有助于解析以下电子邮件的字段(日期、主题、发件人、发件人)的 Java 库?

Message-ID: <19815303.1075861029555.JavaMail.ss@kk>
Date: Wed, 6 Mar 2010 12:32:20 -0800 (PST)
From: someone@someotherplace.com
To: someone@someplace.com
Subject: some subject
Mime-Version: 1.0
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
X-From: one, some <some.one@someotherplace.com>
X-To: one
X-cc: 
X-bcc: 
X-Folder: Bob\Inbox
X-Origin: Bob-R
X-FileName: rbob (Non-Privileged).pst


some message
4

3 回答 3

36

JavaMail是一个 oracle 库,在 javax.mail 包中提供邮件服务和邮件相关服务(如解析常规和 MIME 消息)。此外,Apache 有一个用于邮件处理的Commons Email库。

在 JavaMail api 中,解析包含电子邮件消息(可能是也可能不是明确的 MIME)的字符串的简单方法如下

String content = ...
Session s = Session.getInstance(new Properties());
InputStream is = new ByteArrayInputStream(content.getBytes());
MimeMessage message = new MimeMessage(s, is);

并解析标题可以像这样完成

message.getAllHeaderLines();
for (Enumeration<Header> e = message.getAllHeaders(); e.hasMoreElements();) {
    Header h = e.nextElement();
    h.getName();
    h.getValue();
}
于 2010-08-09T22:34:18.847 回答
10

我遇到了 JavaMail 的问题(它无法解析一些它应该解析的电子邮件)。

我使用Mime4J获得了更好的结果。

于 2012-08-13T03:07:54.410 回答
7

我建议你使用email-mime-parser

以下示例代码为您提供了所需的所有相关信息:

ContentHandler contentHandler = new CustomContentHandler();

MimeConfig mime4jParserConfig = new MimeConfig();
BodyDescriptorBuilder bodyDescriptorBuilder = new DefaultBodyDescriptorBuilder();
MimeStreamParser mime4jParser = new MimeStreamParser(mime4jParserConfig,DecodeMonitor.SILENT,bodyDescriptorBuilder);
mime4jParser.setContentDecoding(true);
mime4jParser.setContentHandler(contentHandler);

InputStream mailIn = 'Provide email mime stream here';
mime4jParser.parse(mailIn);

Email email = ((CustomContentHandler) contentHandler).getEmail();

List<Attachment> attachments =  email.getAttachments();

Attachment calendar = email.getCalendarBody();
Attachment htmlBody = email.getHTMLEmailBody();
Attachment plainText = email.getPlainTextEmailBody();

String to = email.getToEmailHeaderValue();
String cc = email.getCCEmailHeaderValue();
String from = email.getFromEmailHeaderValue();
于 2016-10-06T06:50:07.087 回答