1

我到处寻找，由于某种原因，通过 ajax 发布时我无法将数据发送到我的控制器。

jQuery：

        var newDate = {};
        newDate['start'] = startyear+"-"+startmonth+"-"+startday+" "+starthour+":"+startminute+":00";
        newDate['end'] = endyear+"-"+endmonth+"-"+endday+" "+endhour+":"+endminute+":00";
        newDate['allday'] = allday;
        console.log(JSON.stringify(newDate));
        var url = plgFcRoot + "events/update/"+event.id;
        $.ajax({
            type: 'POST',
            url: url,
            data: JSON.stringify(newDate),
            dataType: "json",
            contentType: "application/json; charset=utf-8",
        })
        .done( function( data ) {
            console.log( data );
        })
        .fail(function( data ) {
            console.log( data );
        });

字符串化时我在控制台中得到这个：

{"start":"2015-12-7 21:30:00","end":"2015-12-7 22:30:00","allday":0}

我试图将数据作为控制器的响应发回：

public function update($id = null)
{
    $event = $this->Events->get($id);
    $event = $this->Events->patchEntity($event, $this->request->data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body($this->request->data());
    return $this->response;
}
4

2 回答 2

1

jQuery 为您处理在 $.ajax() 中传递到“数据”的对象的 urlencoding。这应该可以解决问题：

var newDate = {};
    newDate['start'] = startyear+"-"+startmonth+"-"+startday+" "+starthour+":"+startminute+":00";
    newDate['end'] = endyear+"-"+endmonth+"-"+endday+" "+endhour+":"+endminute+":00";
    newDate['allday'] = allday;
    console.log(JSON.stringify(newDate));
    var url = plgFcRoot + "events/update/"+event.id;
    $.ajax({
        type: 'POST',
        url: url,
        // NOTICE JSON.stringify() has been removed!
        data: newDate
    })
    .done( function( data ) {
        console.log( data );
    })
    .fail(function( data ) {
        console.log( data );
    });

或者，如果您 100% 热衷于将 JSON 作为请求正文传递，您可以使用请求中的输入法解码数据：

public function update($id = null)
{
    $event = $this->Events->get($id);
    $request_data = $this->request->input('json_decode');
    $event = $this->Events->patchEntity($event, $request_data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body(json_encode($request_data));
    return $this->response;
}

我会更多地阅读 CakePHP 3 的JSON 和 XML 视图文档。

于 2015-12-28T21:40:40.467 回答
0

你可以试试这个

public function update($id = null)
{
    $event = $this->Events->get($id);
    $data = json_decode($this->request->data);
    $event = $this->Events->patchEntity($event, $data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body($this->request->data);
    return $this->response;
}
于 2016-07-20T12:38:56.300 回答