17

我正在使用Spring Boot用户必须登录的地方开发演示 REST 服务，以便执行某些操作子集。使用该简单配置添加Swagger UI（使用库）后：springfox

@Bean
public Docket docApi() {
    return new Docket(DocumentationType.SWAGGER_2)
            .select()
                .apis(any())
                .paths(PathSelectors.ant("/api/**"))
                .build()
            .pathMapping("/")
            .apiInfo(apiInfo())
            .directModelSubstitute(LocalDate.class, String.class)
            .useDefaultResponseMessages(true)
            .enableUrlTemplating(true);
}

我最终得到了Swagger UI页面上列出的所有操作的所有 api。不幸的是，我没有在其中列出登录/注销端点。

问题是无法通过Swagger UI内置表单执行部分操作（我发现它非常好的功能并希望让它工作），因为用户没有登录。有没有解决这个问题的方法？我可以手动定义一些端点Swagger吗？

如果有提交凭据的表单（即登录/注销端点），我可以在使用该安全端点之前执行授权。然后，Swagger用户可以token/sessionid从响应中提取并将其粘贴到通过定义的自定义查询参数中@ApiImplicitParams。

您可以在下面找到我的安全配置：

@Override
protected void configure(HttpSecurity http) throws Exception {
    http
            .formLogin()
                .loginProcessingUrl("/api/login")
                .usernameParameter("username")
                .passwordParameter("password")
                .successHandler(new CustomAuthenticationSuccessHandler())
                .failureHandler(new CustomAuthenticationFailureHandler())
                .permitAll()
                .and()
            .logout()
                .logoutUrl("/api/logout")
                .logoutSuccessHandler(new CustomLogoutSuccessHandler())
                .deleteCookies("JSESSIONID")
                .permitAll()
                .and()
            .csrf()
                .disable()
            .exceptionHandling()
                .authenticationEntryPoint(new CustomAuthenticationEntryPoint())
                .and()
            .authorizeRequests()
            .and()
                .headers()
                .frameOptions()
                .disable();
}

@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
    auth
            .userDetailsService(userDetailsService)
            .passwordEncoder(passwordEncoder());
}
4

4 回答 4

14

聚会有点晚了，但是由于 SpringFox 依赖 Spring bean 来构建文档，我们可以轻松地操作它。希望这可以帮助某人！

将其注册为 bean

@Primary
@Bean
public ApiListingScanner addExtraOperations(ApiDescriptionReader apiDescriptionReader, ApiModelReader apiModelReader, DocumentationPluginsManager pluginsManager)
{
    return new FormLoginOperations(apiDescriptionReader, apiModelReader, pluginsManager);
}

用于手动添加任何操作的类：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.LinkedList;
import java.util.List;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpMethod;

import com.fasterxml.classmate.TypeResolver;
import com.google.common.collect.Multimap;

import springfox.documentation.builders.ApiListingBuilder;
import springfox.documentation.builders.OperationBuilder;
import springfox.documentation.builders.ParameterBuilder;
import springfox.documentation.schema.ModelRef;
import springfox.documentation.service.ApiDescription;
import springfox.documentation.service.ApiListing;
import springfox.documentation.service.Operation;
import springfox.documentation.spring.web.plugins.DocumentationPluginsManager;
import springfox.documentation.spring.web.readers.operation.CachingOperationNameGenerator;
import springfox.documentation.spring.web.scanners.ApiDescriptionReader;
import springfox.documentation.spring.web.scanners.ApiListingScanner;
import springfox.documentation.spring.web.scanners.ApiListingScanningContext;
import springfox.documentation.spring.web.scanners.ApiModelReader;

public class FormLoginOperations extends ApiListingScanner
{
    @Autowired
    private TypeResolver typeResolver;

    @Autowired
    public FormLoginOperations(ApiDescriptionReader apiDescriptionReader, ApiModelReader apiModelReader, DocumentationPluginsManager pluginsManager)
    {
        super(apiDescriptionReader, apiModelReader, pluginsManager);
    }

    @Override
    public Multimap<String, ApiListing> scan(ApiListingScanningContext context)
    {
        final Multimap<String, ApiListing> def = super.scan(context);

        final List<ApiDescription> apis = new LinkedList<>();

        final List<Operation> operations = new ArrayList<>();
        operations.add(new OperationBuilder(new CachingOperationNameGenerator())
            .method(HttpMethod.POST)
            .uniqueId("login")
            .parameters(Arrays.asList(new ParameterBuilder()
                .name("username")
                .description("The username")
                .parameterType("query")            
                .type(typeResolver.resolve(String.class))
                .modelRef(new ModelRef("string"))
                .build(), 
                new ParameterBuilder()
                .name("password")
                .description("The password")
                .parameterType("query")            
                .type(typeResolver.resolve(String.class))
                .modelRef(new ModelRef("string"))
                .build()))
            .summary("Log in") // 
            .notes("Here you can log in")
            .build());
        apis.add(new ApiDescription("/api/login/", "Authentication documentation", operations, false));

        def.put("authentication", new ApiListingBuilder(context.getDocumentationContext().getApiDescriptionOrdering())
            .apis(apis)
            .description("Custom authentication")
            .build());

        return def;
    }
}

渲染 Swagger json：

"/api/login/" : {
      "post" : {
        "summary" : "Log in",
        "description" : "Here you can log in",
        "operationId" : "loginUsingPOST",
        "parameters" : [ {
          "name" : "username",
          "in" : "query",
          "description" : "The username",
          "required" : false,
          "type" : "string"
        }, {
          "name" : "password",
          "in" : "query",
          "description" : "The password",
          "required" : false,
          "type" : "string"
        } ]
      }
    }
于 2017-03-10T14:13:55.963 回答
6

你可以在你的 API 中添加一个虚假的登录和注销方法来生成 Swagger 文档，它会被 Spring Security 过滤器自动覆盖。

@ApiOperation("Login.")
@PostMapping("/login")
public void fakeLogin(@ApiParam("User") @RequestParam String email, @ApiParam("Password") @RequestParam String password) {
    throw new IllegalStateException("This method shouldn't be called. It's implemented by Spring Security filters.");
}

@ApiOperation("Logout.")
@PostMapping("/logout")
public void fakeLogout() {
    throw new IllegalStateException("This method shouldn't be called. It's implemented by Spring Security filters.");
}
于 2017-07-29T03:56:35.590 回答
4

只是添加一点修正。如果您想发出真正的 POST 请求（例如通过 swagger-ui 的 HTML 页面），您需要对 Morten 的答案进行少许更改。

Morten的代码向 /login 发出 POST 请求，如下所示：

http://<hostname>/api/login?username=<user>&password=<password>

但是如果你想发出一个 POST 请求，你需要传递一个正文，而不仅仅是查询参数。为此，您需要添加具有名称body和参数类型的参数，body如下所示：

@Override
public Multimap<String, ApiListing> scan(ApiListingScanningContext context)
{
    final Multimap<String, ApiListing> def = super.scan(context);

    final List<ApiDescription> apis = new LinkedList<>();

    final List<Operation> operations = new ArrayList<>();
    operations.add(new OperationBuilder(new CachingOperationNameGenerator())
        .method(HttpMethod.POST)
        .uniqueId("login")
        .parameters(Arrays.asList(new ParameterBuilder()
            .name("body")
            .required(true)
            .description("The body of request")
            .parameterType("body")            
            .type(typeResolver.resolve(String.class))
            .modelRef(new ModelRef("string"))
            .build()))
        .summary("Log in") // 
        .notes("Here you can log in")
        .build());
    apis.add(new ApiDescription("/api/login/", "Authentication documentation", operations, false));

    def.put("authentication", new ApiListingBuilder(context.getDocumentationContext().getApiDescriptionOrdering())
        .apis(apis)
        .description("Custom authentication")
        .build());

    return def;
}

现在我们可以通过 POST 请求传递一个正文。主体可以是 JSON，例如：

{"username":"admin","password":"admin"}

于 2017-03-24T14:31:20.177 回答
1

您可以使用描述身份验证 API 的接口。实际的实现由 Spring Security 提供。（这是Italo 答案的变体，其中使用接口而不是假实现。）

/**
 * Authentication API specification for Swagger documentation and Code Generation.
 * Implemented by Spring Security.
 */
@Api("Authentication")
@RequestMapping(value = "/", produces = MediaType.APPLICATION_JSON_VALUE)
public interface AuthApi {
    /**
     * Implemented by Spring Security
     */
    @ApiOperation(value = "Login", notes = "Login with the given credentials.")
    @ApiResponses({@ApiResponse(code = 200, message = "", response = Authentication.class)})
    @RequestMapping(value = "/login", method = RequestMethod.POST)
    default void login(
        @RequestParam("username") String username,
        @RequestParam("password") String password
    ) {
        throw new IllegalStateException("Add Spring Security to handle authentication");
    }

    /**
     * Implemented by Spring Security
     */
    @ApiOperation(value = "Logout", notes = "Logout the current user.")
    @ApiResponses({@ApiResponse(code = 200, message = "")})
    @RequestMapping(value = "/logout", method = RequestMethod.POST)
    default void logout() {
        throw new IllegalStateException("Add Spring Security to handle authentication");
    }
}
于 2017-08-28T14:17:11.080 回答