4

我得到异常“ http://api.openweathermap.org/data/2.5/weather?q=Sydney ”。有人可以帮助如何使用它。当我粘贴以下内容时,可以在网络浏览器上正常工作

http://api.openweathermap.org/data/2.5/weather?q=Sydney&APPID=ea574594b9d36ab688642d5fbeab847e

我也尝试了以下组合,但没有运气

connection.addRequestProperty("x-api-key",
                    "&APPID=cea574594b9d36ab688642d5fbeab847e");


private static final String OPEN_WEATHER_MAP_API =
        "http://api.openweathermap.org/data/2.5/weather?q=%s";


public static JSONObject getJSON(String city) {
    try {
        URL url = new URL(String.format(OPEN_WEATHER_MAP_API, city));

        HttpURLConnection connection = (HttpURLConnection) url.openConnection();

        connection.addRequestProperty("x-api-key",
                "cea574594b9d36ab688642d5fbeab847e");

        BufferedReader reader =
                new BufferedReader(new InputStreamReader(connection.getInputStream()));

        StringBuffer json = new StringBuffer(1024);
        String tmp = "";

        while((tmp = reader.readLine()) != null)
            json.append(tmp).append("\n");
        reader.close();

        JSONObject data = new JSONObject(json.toString());

        if(data.getInt("cod") != 200) {
            System.out.println("Cancelled");
            return null;
        }

        return data;
    } catch (Exception e) {

        System.out.println("Exception "+ e.getMessage());
        return null;
    }  
4

4 回答 4

17

1.-在您的应用程序上添加互联网权限 如何向android应用程序添加清单权限?

2.-这里有一个关于如何实现 api 调用的示例

 public class MainActivity extends Activity {

    JSONObject data = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        getJSON("Sydney");
    }

    public void getJSON(final String city) {

        new AsyncTask<Void, Void, Void>() {


            @Override
            protected void onPreExecute() {
                super.onPreExecute();

            }

            @Override
            protected Void doInBackground(Void... params) {
                try {
                    URL url = new URL("http://api.openweathermap.org/data/2.5/weather?q="+city+"&APPID=ea574594b9d36ab688642d5fbeab847e");

                    HttpURLConnection connection = (HttpURLConnection) url.openConnection();

                    BufferedReader reader =
                            new BufferedReader(new InputStreamReader(connection.getInputStream()));

                    StringBuffer json = new StringBuffer(1024);
                    String tmp = "";

                    while((tmp = reader.readLine()) != null)
                        json.append(tmp).append("\n");
                    reader.close();

                    data = new JSONObject(json.toString());

                    if(data.getInt("cod") != 200) {
                        System.out.println("Cancelled");
                        return null;
                    }


                } catch (Exception e) {

                    System.out.println("Exception "+ e.getMessage());
                    return null;
                }

                return null;
            }

            @Override
            protected void onPostExecute(Void Void) {
            if(data!=null){
                Log.d("my weather received",data.toString());
            }

            }
        }.execute();

    }
}

在此处输入图像描述

于 2015-12-16T21:27:56.833 回答
2

看起来开放天气可能会遇到问题。我这样说是因为他们给出的示例返回与您相同的错误消息。从他们的网站>> http://openweathermap.org/appid

API 调用示例(没有有效密钥):

api.openweathermap.org/data/2.5/forecast/city?id=524901&APPID=1111111111
于 2015-12-16T20:54:18.877 回答
1

尝试这个

  1. 创建一个名为 GetData 的类

    class GetData extends AsyncTask <String,Void,String> {
    
            @Override
            protected String doInBackground(String... params) {
                // TODO Auto-generated method stub
                String result = "";
                HttpURLConnection conn = null;
                try {
                    URL url = new URL("http://api.openweathermap.org/data/2.5/weather?q="+URLEncoder.encode(params[0], "UTF-8")+"&APPID=ea574594b9d36ab688642d5fbeab847e");
                    conn = (HttpURLConnection) url.openConnection();
                    InputStream in = new BufferedInputStream(conn.getInputStream());
                    if (in != null) {
                        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(in));
                        String line = "";
    
                        while ((line = bufferedReader.readLine()) != null)
                            result += line;
                    }
                    in.close();
                    return result;
                } catch (IOException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
                finally {
                    if(conn!=null)
                    conn.disconnect();
                }
                return result;
            }
    
            @Override
            protected void onPostExecute(String result) {
                // TODO Auto-generated method stub
                super.onPostExecute(result);
                Toast.makeText(getApplicationContext(), result, Toast.LENGTH_LONG).show();
            }
    
    }
    
  2. 然后用它来获取数据

    new Getdata().execute("your city or country");

于 2015-12-16T20:55:33.270 回答
0

使用改造的工作样本

    val apiService = 
    API.getInstance().retrofit.create(MyApiEndpointInterface::class.java)

    val params = HashMap<String, String>()
    params["q"] =  "London,uk"
    params["APPID"] = "b6907d289e10d714a6e88b30761fae22"

    val call = apiService.getUser(params)

    call.enqueue(object : Callback<WeatherResponse> {
        override fun onFailure(call: Call<WeatherResponse>?, t: Throwable?) {
            Log.e("Error:::","Error "+t!!.message)
        }

        override fun onResponse(call: Call<WeatherResponse>?, response: Response<WeatherResponse>?) {
            if (response != null && response.isSuccessful && response.body() != null) {
                Log.e("SUCCESS:::","Response "+ response.body()!!.main.temp)

               // val tempCel = ((response.body()!!.main.temp - 32)*5)/9
                val tempCel = (response.body()!!.main.temp  - 273.15f)

                temperature.setText("${tempCel.roundToInt()}°C")

            }
        }

    })
于 2019-01-30T13:57:54.943 回答