ruby-on-rails - 两种模型的一种方法。如何将模型名称作为变量传递给控制器​​？

Question

我在两个不同的控制器（帖子和板）中有两种方法。它们几乎相同。区别只是模型-实例-关联名称。为了干燥这个我想在模块中编写方法，但是如何在 Post 和 Board 之间共享它？

def init_post_comments
    @user = current_user
    a = @user.posts.pluck(:id) # not very nice...
    b=params[:post_ids] ||= []
    b = b.map(&:to_i)
    follow = b - a
    unfollow = a - b
    follow.each do |id| # checkbox just checked
      @post = Post.find_by_id(id)
      if @post.users.empty?
        @post.update_attribute(:new_follow, true)
      end
      @user.posts << @post
    end
    unfollow.each do |id| # if checkbox was unchecked
      @post = Post.find_by_id(id)
      remove_post_from_user(@post)# here we destroy association
    end
    if follow.size > 0
      get_post_comments_data
    end

    redirect_to :back

  end

更新好的，如果我将方法转移到模型的关注点，我应该如何在这里处理关联？在这里@user.posts.pluck(:id)和这里@user.boards.pluck(:id)，我可以用什么来替换帖子和板，以便它可以与它们一起使用？

Answer 1

所以，我做到了！我不知道这是否正确，但我干燥了这段代码。

两个控制器：

posts_controller.rb

def init_comments
    if Post.comments_manipulator(current_user, params[:post_ids] ||= []) > 0
      @posts = Post.new_post_to_follow  
      code = []
      @posts.each do |post|
        group = post.group
        code = code_constructor('API.call')
      end
      Post.comments_init(get_request(code), @posts)
    end
    redirect_to :back
  end

boards_controller.rb

def init_comments
    if Board.comments_manipulator(current_user, params[:board_ids] ||= []) > 0
      @boards = Board.new_board_to_follow
      code = []
      @boards.each do |board|# подготовка запроса
        group = board.group
        code = code_constructor('API.call')
      end
      Board.comments_init(get_request(code), @boards)
    end
    redirect_to :back
  end

正如你所看到的，它们是完全一样的。在模型board.rb和post.rb-include CommentsInitializer

而在models\concerns

module CommentsInitializer
  extend ActiveSupport::Concern

module ClassMethods
  def comments_manipulator(user, ids)
    relationship = self.name.downcase + 's'
    a = user.send(relationship).pluck(:id)
    b = ids.map(&:to_i)
    follow = b - a
    unfollow = a - b
    follow.each do |id| # start to follow newly checked obj
      @obj = self.find_by_id(id)
      if @obj.users.empty?
        @obj.update_attribute(:new_follow, true)
      end
      user.send(relationship) << @obj
    end

    unfollow.each do |id| # remove from following
      @obj = self.find_by_id(id)
      remove_assoc_from_user(@obj, user)#destroy relation with current user
    end

    follow.size
  end

  def comments_init(comments, objs)
    i = 0
    objs.each do |obj| # updating comments data
      if comments[i]['count'] == 0
        obj.update(new_follow: false)
      else
        obj.update(new_follow: false, last_comment_id: comments[i]['items'][0]['id'])
      end
      i += 1
    end
  end

  def remove_assoc_from_user(obj, user)
    user = user.id
    if user
      obj.users.delete(user)
    end
  end
end

我的代码有效。如果您知道如何使它更好，请回答！