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假设我们有这个身份不明的DIV

  <div class="class-occurs-many-times-on-page">foo</div>

我们想在它之后放置另一个包含数十或数百个 SPAN 元素的未识别 DIV：

<div class="a-class-that-occurs-many-times-on-page">foo</div>
<div class="another-class-that-occurs-many-times-on-page">
        <span class="latin">lorem</span><span class="latin">ipse</span>
        <span class="swedish-chef">føø</span><span class="swedish-chef">bår</span>
        .
        .
        .
        <span>...</span>
</div>

我们已经添加了第一个未识别的 DIV，并希望以这种方式添加 SPAN-container DIV：

 values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"},
 {word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}];

 $("#" +  someParentElement).append(
     $("<div></div>").addClass("a-class-that-occurs-many-times-on-page").text("foo").after(

            $("<div></div>").addClass("another-class-that-occurs-many-times-on-page").append(
                 function(index, html){                    
                     // how to wrap each value in the values array in a span
                     // and inject each of those spans into this DIV?

                 }
            )

      )


 );

这种方法是否可行，如果可以，如果目标是将数组中的每个值包装在 SPAN 中并注入，那么 .append() 方法调用中的函数必须对 values 数组的每次迭代执行什么操作跨度到容器中？

谢谢

4

1 回答 1

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values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"}, {word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}],
len    = values.length,
$ctn   = $('<div/>', {
     class:   'another-class-that-occurs-many-times-on-page'
}),
buildarr = [];

while(len--){
    buildarr.push('<span>');
    buildarr.push(values[len].word);
    buildarr.push(values[len].cls);
    buildarr.push('</span>');
}

$ctn.append(buildarr.join('')).appendTo(document.body);

这只是一个建议，就像你可以完成那种任务一样。它假定我们必须填充数组的顺序是无关紧要的（通过以最快的方式循环，reversed while）。如果订单很重要，请使用standard for loop.

于 2010-08-06T12:46:05.233 回答