How to solve error of getting same user information in login with Facebook for different user in my web application developed in Java?
这是连接 facebook 的主要连接类。
public class FBConnection
{
public static final String FB_APP_ID = "1729*******";
public static final String FB_APP_SECRET = "2c5******";
public static final String REDIRECT_URI = "http://example.com";
static String accessToken = "";
此方法提供了从 facebook 获取访问令牌的代码。
public String getFBAuthUrl() {
String fbLoginUrl = "";
try {
fbLoginUrl = "http://www.facebook.com/dialog/oauth?" + "client_id="
+ FBConnection.FB_APP_ID + "&redirect_uri="
+ URLEncoder.encode(FBConnection.REDIRECT_URI, "UTF-8")
+ "&scope=email,public_profile";
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
return fbLoginUrl;
}
此方法将生成图形 url 以获取访问令牌。
public String getFBGraphUrl(String code) {
String fbGraphUrl = "";
try {
fbGraphUrl = "https://graph.facebook.com/oauth/access_token?"
+ "client_id=" + FBConnection.FB_APP_ID + "&redirect_uri="
+ URLEncoder.encode(FBConnection.REDIRECT_URI, "UTF-8")
+ "&client_secret=" + FB_APP_SECRET + "&code=" + code;
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
return fbGraphUrl;
}
此方法从重定向 url 获取的代码中获取访问令牌。
public String getAccessToken(String code) {
if ("".equals(accessToken)) {
URL fbGraphURL;
try {
fbGraphURL = new URL(getFBGraphUrl(code));
} catch (MalformedURLException e) {
e.printStackTrace();
throw new RuntimeException("Invalid code received " + e);
}
URLConnection fbConnection;
StringBuffer b = null;
try {
fbConnection = fbGraphURL.openConnection();
BufferedReader in;
in = new BufferedReader(new InputStreamReader(fbConnection.getInputStream()));
String inputLine;
b = new StringBuffer();
while ((inputLine = in.readLine()) != null)
b.append(inputLine + "\n");
in.close();
} catch (IOException e) {
e.printStackTrace();
throw new RuntimeException("Unable to connect with Facebook " + e);
}
accessToken = b.toString();
if (accessToken.startsWith("{")) {
throw new RuntimeException("ERROR: Access Token Invalid: " + accessToken);
}
}
return accessToken;
}