13

早安伙计们，

我有一个来自 List 并具有公共属性的集合。Xml 序列化程序不接受我的财产。列表项可以很好地序列化。我试过 XmlAttribute 属性无济于事。各位有解决办法吗？

    public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();
    }
    private void button1_Click(object sender, RoutedEventArgs e)
    {
        var people = new PersonCollection
        {
            new Person { FirstName="Sue", Age=17 },
            new Person { FirstName="Joe", Age=21 }
        };
        people.FavoritePerson = "Sue";

        var x = new XmlSerializer(people.GetType());
        var b = new StringBuilder();
        var w = XmlTextWriter.Create(b, new XmlWriterSettings { NewLineChars = "\r\n", Indent = true });
        x.Serialize(w, people);
        var s = b.ToString();
    }
}

[XmlRoot(ElementName="People")]
public class PersonCollection : List<Person>
{
    //DOES NOT WORK! ARGHHH
    [XmlAttribute]
    public string FavoritePerson { get; set; }    
}

public class Person
{
    [XmlAttribute]
    public string FirstName { get; set; }
    [XmlAttribute]
    public int Age { get; set; }
}

我得到以下xml

<?xml version="1.0" encoding="utf-16"?>
        <People xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
          <Person FirstName="Sue" Age="17" />
          <Person FirstName="Joe" Age="21" />
        </People>

我想得到这个

<?xml version="1.0" encoding="utf-16"?>
        <People FavoritePerson="Sue" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
          <Person FirstName="Sue" Age="17" />
          <Person FirstName="Joe" Age="21" />
        </People>
4

3 回答 3

5

我继续通过实现 IXmlSerializable 解决了这个问题。如果存在更简单的解决方案，请发布！

    [XmlRoot(ElementName="People")]
public class PersonCollection : List<Person>, IXmlSerializable
{
    //IT WORKS NOW!!! Too bad we have to implement IXmlSerializable
    [XmlAttribute]
    public string FavoritePerson { get; set; }

    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }
    public void ReadXml(XmlReader reader)
    {
        FavoritePerson = reader[0];            
        while (reader.Read())
        {
            if (reader.Name == "Person")
            {
                var p = new Person();
                p.FirstName = reader[0];
                p.Age = int.Parse( reader[1] ); 
                Add(p);
            }
        }
    }
    public void WriteXml(XmlWriter writer)
    {
        writer.WriteAttributeString("FavoritePerson", FavoritePerson);
        foreach (var p in this)
        {
            writer.WriteStartElement("Person");
            writer.WriteAttributeString("FirstName", p.FirstName);
            writer.WriteAttributeString("Age", p.Age.ToString());
            writer.WriteEndElement();            
        }
    }
}
于 2010-08-05T17:32:20.200 回答
3

这不是问题的答案，但我想我会提出一个建议来简化代码开发。

向类中添加一个新Add方法，如下所示：PersonCollection

public class PersonCollection : List<Person>, IXmlSerializable
{
...
    public void Add(string firstName, int age)
    {
        this.Add(new Person(firstName, age));
    }
...
}

然后，通过这样做，您可以将集合初始值设定项语法简化为：

var people = new PersonCollection
{
    { "Sue", 17 },
    { "Joe", 21 }
};
people.FavoritePerson = "Sue";
于 2010-08-06T15:13:45.690 回答
1

如果您不介意包装所有列表函数，那么您可以将列表嵌入为类的属性，而不是从它派生。

然后，您将使用 XmlElement 属性强制将 xml 元素写为平面列表（而不是嵌套）。

于 2011-09-16T08:21:58.380 回答