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I want to alternate colors in a stacked bar graph in matplotlib..so as I can get different colors for the graphs depending on their type. I have two types except that they do not alternate regularly. so I need to check their type before I choose the colors.

The problem is that it is conditional. I provide the type in an array, but there is no way to do it at the level of the plt.bar(.............)...well I think.

p1 = plt.bar(self.__ind,
                    self.__a,
                    self.__width, 
                    color='#263F6A')

p2 = plt.bar(self.__ind,
                    self.__b,
                    self.__width, 
                    color='#3F9AC9',
                    bottom = self.__arch)

p3 = plt.bar(self.__ind,
                    self.__c,
                    self.__width, 
                    color='#76787A',
                    bottom = self.__a + self.__b)

self.__a and self.__b and self.__c are all data lists that I need to plot in the same figure and I have another list of types for each element of the mentioned lists above. I only want to know how could I make it possible to change the colors of the graphs depending on the type provided by the types list and at the same time keeping all the bars in one plot.

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1 回答 1

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当你说这self.__a是一个列表时，我很困惑 - 当我尝试绘制一个列表时：

In [19]: plt.bar(1,[1,2,3], 0.1, color='#ffcc00')

我明白了

AssertionError: incompatible sizes: argument 'height' must be length 1 or scalar

但是，您可以做的是在循环中绘制您的值：

# Setup code here...

indices = [1,2,3,4]
heights = [1.2, 2.2, 3.3, 4.4]
widths = [0.1, 0.1, 0.2, 1]
types = ['spam', 'rabbit', 'spam', 'grail']


for index, height, width, type in zip(indices, heights, widths, types):
    if type == 'spam':
        plt.bar(index, height, width, color='#263F6A')
    elif type == 'rabbit':
        plt.bar(index, height, width, color='#3F9AC9', bottom = self.__arch)
    elif type == 'grail':
        plt.bar(index, height, width, color='#76787a', bottom = 3)
于 2010-08-05T15:19:24.407 回答