1

我正在尝试执行此 Java 代码：

PowerManager pm = (PowerManager) getSystemService(Context.POWER_SERVICE);
PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.SCREEN_DIM_WAKE_LOCK, "My Tag");
wl.acquire();

使用 Qt QAndroidJniObject（我正在 Android 上部署 Qt 应用程序）。

我这样做了：

QAndroidJniObject activity = QAndroidJniObject::callStaticObjectMethod("org/qtproject/qt5/android/QtNative", "activity", "()Landroid/app/Activity;");
if ( activity.isValid() )
{
    QAndroidJniObject serviceName = QAndroidJniObject::getStaticObjectField<jstring>("android/content/Context","POWER_SERVICE");
    if ( serviceName.isValid() )
    {
        QAndroidJniObject powerMgr = activity.callObjectMethod("getSystemService", "(Ljava/lang/String;)Ljava/lang/Object;",serviceName.object<jobject>());
        if ( powerMgr.isValid() )
        {
            jint levelAndFlags = QAndroidJniObject::getStaticField<jint>("android/os/PowerManager","SCREEN_DIM_WAKE_LOCK");

            QAndroidJniObject tag = QAndroidJniObject::fromString( "My Tag" );

            QAndroidJniObject wakeLock = powerMgr.callObjectMethod("newWakeLock", "(ILjava/lang/String;)Landroid/os/PowerManager/WakeLock;", levelAndFlags,tag.object<jstring>());

            if ( wakeLock.isValid() )
                wakeLock.callMethod<void>("acquire", "()V");
            else
                assert( false );
        }
    }
}

从调试器检查：levelAndFlags是正确的 (6)，tag是正确的（“我的标签”），但wakeLock.isValid()返回 false。

这行肯定有问题：

QAndroidJniObject wakeLock = powerMgr.callObjectMethod("newWakeLock", "(ILjava/lang/String;)Landroid/os/PowerManager/WakeLock;", levelAndFlags,tag.object<jstring>());

但我想不通是什么...

4

1 回答 1

0

嵌套类名需要特殊的语法：

Landroid/os/PowerManager/WakeLock

应该：

Landroid/os/PowerManager$WakeLock

它有效！

于 2015-12-09T12:59:51.370 回答