我编写了与progn
. 我如何告诉 emacs 这个函数应该以与 相同的方式缩进progn
?
问问题
754 次
2 回答
7
这应该这样做
(put 'myfunc 'lisp-indent-function 0)
文档lisp-indent-function
(由 找到C-h f lisp-indent-function RET):
lisp-indent-function is a compiled Lisp function in `lisp-mode.el'.
(lisp-indent-function indent-point state)
This function is the normal value of the variable
`lisp-indent-function`. It is used when indenting a line within
a function call, to see if the called function says anything
special about how to indent the line.
indent-point is the position where the user typed TAB, or
equivalent. Point is located at the point to indent under
(for default indentation); state is the `parse-partial-sexp`
state for that position.
If the current line is in a call to a Lisp function which has
a non-nil property `lisp-indent-function`, that specifies how
to do the indentation. The property value can be:
* `defun`, meaning indent `defun`-style;
* an integer N, meaning indent the first N arguments specially
like ordinary function arguments and then indent any further
arguments like a body;
* a function to call just as this function was called. If that
function returns nil, that means it doesn't specify
the indentation.
This function also returns nil meaning don't specify the
indentation.
于 2010-08-05T06:04:40.483 回答
3
因为它“实际上是一个宏”:
C-hig (elisp) Indenting Macros
RET
在这种情况下:
(defmacro my-macro (&rest body)
"Does things"
(declare (indent defun))
`(progn ,@body))
(my-macro
(message "foo")
(message "bar"))
于 2013-05-11T11:59:42.510 回答