1

我正在尝试更新 mysql 多个表，虽然没有错误但更改未反映在 mysql 数据库中。如果我需要使用 JOIN 将查询更新放在一个字符串中，请告诉我。

我还需要吗

mysqli_query($conn, $sqlCD) or die(mysqli_error($conn)); in the below ? 

  $pCDTitle = filter_has_var(INPUT_GET, 'CDTitle') ? $_GET['CDTitle']: null;         // store all parameter in variable
  $pCDPubName = filter_has_var(INPUT_GET, 'CDPub') ? $_GET['CDPub']: null;
  $pCDYear = filter_has_var(INPUT_GET, 'CDYear') ? $_GET['CDYear']: null;
  $pCDCategory = filter_has_var(INPUT_GET, 'CDCat') ? $_GET['CDCat']: null;        
  $pCDPrice = filter_has_var(INPUT_GET, 'CDPrice') ? $_GET['CDPrice']: null;
  $pCDID = filter_has_var(INPUT_GET, 'CDID') ? $_GET['CDID']: null;
  $pCDPubID = filter_has_var(INPUT_GET, 'pubID') ? $_GET['pubID']: null;    

$sqlCD = mysql_query("UPDATE nmc_cd SET CDTitle='$pCDTitle', CDYear='$pCDYear', CDPrice='$pCDPrice'");
$sqlCD2 = mysql_query("UPDATE nmc_category SET catDesc='$pCDCategory'");
$sqlCD3 = mysql_query("UPDATE nmc_publisher SET pubName='$pCDPubName'");

//mysqli_query($conn, $sqlCD) or die(mysqli_error($conn));
//mysqli_query($conn, $sqlCD2) or die(mysqli_error($conn));
//mysqli_query($conn, $sqlCD3) or die(mysqli_error($conn));
mysqli_close($conn);
4

2 回答 2

3

您必须更改查询：

$sqlCD = mysql_query("UPDATE nmc_cd SET CDTitle=$pCDTitle, CDYear=$pCDYear, CDPrice=$pCDPrice");
$sqlCD2 = mysql_query("UPDATE nmc_category SET catDesc=$pCDCategory");
$sqlCD3 = mysql_query("UPDATE nmc_publisher SET pubName=$pCDPubName");

原因：如果 Double qoutes "" 中的字符串具有 $test 之类的 php 变量，则其值会自动在字符串中，但如果您使用单 qoute ''，则会打印其变量名。例如：

$test = 5;
echo "The number is $test"; //The number is 5 prints
echo 'The number is $test'; //The number is $test prints
于 2015-11-27T05:17:45.097 回答
1 

mysqli_query($conn, $sqlCD) or die(mysqli_error($conn)); in the below ? 

  $pCDTitle = filter_has_var(INPUT_GET, 'CDTitle') ? $_GET['CDTitle']: null;         // store all parameter in variable
  $pCDPubName = filter_has_var(INPUT_GET, 'CDPub') ? $_GET['CDPub']: null;
  $pCDYear = filter_has_var(INPUT_GET, 'CDYear') ? $_GET['CDYear']: null;
  $pCDCategory = filter_has_var(INPUT_GET, 'CDCat') ? $_GET['CDCat']: null;        
  $pCDPrice = filter_has_var(INPUT_GET, 'CDPrice') ? $_GET['CDPrice']: null;
  $pCDID = filter_has_var(INPUT_GET, 'CDID') ? $_GET['CDID']: null;
  $pCDPubID = filter_has_var(INPUT_GET, 'pubID') ? $_GET['pubID']: null;    

$sqlCD = mysqli_query($conn,"UPDATE nmc_cd SET CDTitle='$pCDTitle', CDYear='$pCDYear', CDPrice='$pCDPrice'") or die(mysqli_error($conn));
$sqlCD2 = mysqli_query($conn,"UPDATE nmc_category SET catDesc='$pCDCategory'") or die(mysqli_error($conn));
$sqlCD3 = mysqli_query($conn,"UPDATE nmc_publisher SET pubName='$pCDPubName'") or die(mysqli_error($conn));
mysqli_close($conn);

尝试这个。

于 2015-11-27T06:10:59.377 回答