from math import sin
from numpy import arange
from pylab import plot,xlabel,ylabel,show
def answer():
print('Part a:')
print(low(x,t))
print('First Graph')
print('')
def low(x,t):
return 1/RC * (V_in - V_out)
a = 0.0
b = 10.0
N = 1000
h = (b-a)/N
RC = 0.01
V_out = 0.0
tpoints = arange(a,b,h)
xpoints = []
x = 0.0
for t in tpoints:
xpoints.append(x)
k1 = h*f(x,t)
k2 = h*f(x+0.5*k1,t+0.5*h)
k3 = h*f(x+0.5*k2,t+0.5*h)
k4 = h*f(x+k3,t+h)
x += (k1+2*k2+2*k3+k4)/6
plot(tpoints,xpoints)
xlabel("t")
ylabel("x(t)")
show()
因此,我对四阶龙格库塔方法进行了编码,但我试图适应的部分是如果 [2t] 为偶数则 V_in(t) = 1 或如果 [2t] 为奇数则为 -1。
另外我不确定我是否应该返回这个等式:return 1/RC * (V_in - V_out)
这是问题所在:
如果您能帮助我,将不胜感激!