我想知道如何在我的 android 应用程序中处理强制停止。该应用程序在 Activity 中包含一个 asynctask 类,如下所示:
private class SocketTask extends AsyncTask<String, Void, SocketAnswer> {
ProgressDialog pd;
@Override
protected void onPreExecute() {
super.onPreExecute();
lockOrientation();
try {
if (pd == null) {
try {
pd = new ProgressDialog(MenuDisplayActivity.this);
} catch (Exception e) {
}
}
pd.setMessage(Global.Labels.get(165).toString());
pd.setCancelable(false);
pd.show();
} catch (Exception e) {
}
}
public SocketTask(MenuDisplayActivity activity) {
try {
pd = new ProgressDialog(activity);
} catch (Exception e) {
}
}
@Override
protected SocketAnswer doInBackground(String... params) {
应用程序运行无任何异常,但是,在用户强制停止后(使用三星 Galaxy S5 主页按钮左侧的菜单按钮),当应用程序重新打开时,它会显示“进度对话框”消息请稍候”位于 asynctask 的 onPreExecute 方法中并无限挂起。
当我调试时,我注意到应用程序挂在 Looper 类循环方法中:
public static void loop() {
final Looper me = myLooper();
if (me == null) {
throw new RuntimeException("No Looper; Looper.prepare() wasn't called on this thread.");
}
final MessageQueue queue = me.mQueue;
// Make sure the identity of this thread is that of the local process,
// and keep track of what that identity token actually is.
Binder.clearCallingIdentity();
final long ident = Binder.clearCallingIdentity();
for (;;) { //The application gets stuck infinitely in this loop
Message msg = queue.next(); // might block
if (msg == null) {
// No message indicates that the message queue is quitting.
return;
}
// This must be in a local variable, in case a UI event sets the logger
Printer logging = me.mLogging;
if (logging != null) {
logging.println(">>>>> Dispatching to " + msg.target + " " +
msg.callback + ": " + msg.what);
}
msg.target.dispatchMessage(msg);
if (logging != null) {
logging.println("<<<<< Finished to " + msg.target + " " + msg.callback);
}
// Make sure that during the course of dispatching the
// identity of the thread wasn't corrupted.
final long newIdent = Binder.clearCallingIdentity();
if (ident != newIdent) {
Log.wtf(TAG, "Thread identity changed from 0x"
+ Long.toHexString(ident) + " to 0x"
+ Long.toHexString(newIdent) + " while dispatching to "
+ msg.target.getClass().getName() + " "
+ msg.callback + " what=" + msg.what);
}
msg.recycle();
}
}
我们如何确保应用程序摆脱这个无限循环?
谢谢你。
此致。