2 
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "My text");
sendIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(http://onman.ir/colorfinder/sample.jpg));
sendIntent.setType("*/*");
sendIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
startActivity(Intent.createChooser(sendIntent, "Share using"));

此代码在与 共享意图时无法附加图像，并且与仅共享多个图像或视频的Gmail共享时也会出错。Facebook当我更改类型时，sendIntent.setType("image/*")它会打开共享窗口，Facebook但带有空白文本和图像。

4

5 回答 5

1

分享你可以使用这个代码

     Intent shareIntent = new Intent();

                   shareIntent.setAction(Intent.ACTION_SEND);
                   shareIntent.setType("image/*");
                   shareIntent.putExtra(Intent.EXTRA_TEXT,"abc");
                   shareIntent.putExtra(Intent.EXTRA_STREAM, imagebitmap);
                  startActivity(Intent.createChooser(shareIntent, "Share using"));

但是如果你想在 facebook 中做它不会通过意图工作你应该使用 facebook sdk 来共享图像和文本

FacebookDialog shareDialog = new FacebookDialog.ShareDialogBuilder(this)
                                   .setLink(url)
                                   .setCaption(getString(R.string.fb_share))
                                   .setDescription(getString(R.string.fb_share))
                                   .setPicture(
                                                 "https://scontent-lhr3-1.xx.fbcdn.net/hphotos-xfp1/v/t1.0-9/11899955_1616850925232395_9146772907853639083_n.jpg?oh=3dd7da7bf03edee84689d66af2024880&oe=56793D62")
                                   .build();
                     uiHelper.trackPendingDialogCall(shareDialog.present());
                     dismissProgressBar();

在您的代码中，您首先要直接共享图像 url，您需要获取位图，然后共享位图而不是 url

于 2015-11-24T09:31:26.750 回答
1

private void shareImage() { Intent share = new Intent(Intent.ACTION_SEND);

// If you want to share a png image only, you can do:
// setType("image/png"); OR for jpeg: setType("image/jpeg");
share.setType("image/*");

// Make sure you put example png image named myImage.png in your
// directory
String imagePath = Environment.getExternalStorageDirectory()
        + "/myImage.png";

File imageFileToShare = new File(imagePath);

Uri uri = Uri.fromFile(imageFileToShare);
share.putExtra(Intent.EXTRA_STREAM, uri);

startActivity(Intent.createChooser(share, "Share Image!"));

试试这个代码

请注意，当您使用 setType() 方法时，您将启用 Android 过滤哪些应用程序可以共享您的内容。例如，您正在共享文本或 URL，要显示的适当应用程序可以是 Facebook、消息或电子邮件。如果您要分享图片，合适的应用程序可以是 Instagram、Snapped 或 Picasa。

于 2015-11-24T09:43:41.800 回答
0 
 @Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == UPLOADIMAGE && resultCode == RESULT_OK)
    {
        uploadImage.setVisibility(View.GONE);
        imageView.setVisibility(View.VISIBLE);

        if (data !=null)
        {
            imageUri=data.getData();
            imageView.setImageURI(imageUri);
            Uri selectedImage = data.getData();
            String[] filePathColumn = { MediaStore.Images.Media.DATA };

            Cursor cursor = getContentResolver().query(selectedImage,filePathColumn, null, null, null);
            cursor.moveToFirst();
            columnIndex = cursor.getColumnIndex(filePathColumn[0]);
            attachmentFile = cursor.getString(columnIndex);
            Log.e("Attachment Path:", attachmentFile);
            URI = Uri.parse("file://" + attachmentFile);
            cursor.close();

        }
        else {Toast.makeText(TutorForm.this,"Uploading image failed",Toast.LENGTH_LONG).show();}




    }
    super.onActivityResult(requestCode, resultCode, data);

OnClickListner

 Intent emailIntent=new Intent(Intent.ACTION_SENDTO, Uri.parse("mailto:"+ clientEmail));
        emailIntent.putExtra(Intent.EXTRA_TEXT,body);
        emailIntent.putExtra(Intent.EXTRA_SUBJECT,"Tutor Registration from App");
        emailIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
        Uri uri = Uri.parse(imageUri.toString());
        emailIntent.putExtra(Intent.EXTRA_STREAM,URI);
        startActivity(Intent.createChooser(emailIntent,"Send Via..."));
于 2017-01-04T12:18:57.217 回答
0 
shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
shareIntent.setType("image/*");

//set your message
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, msgText); 
String imagePath = Environment.getExternalStorageDirectory() + 
File.separator + "image_name.jpg";
File imageFileToShare = new File(imagePath);
Uri uri = Uri.fromFile(imageFileToShare);
shareIntent.putExtra(Intent.EXTRA_STREAM, uri);
Uri uri = Uri.fromFile(imageFileToShare);
sharingIntent.putExtra(Intent.EXTRA_STREAM, uri);
于 2017-09-18T08:29:01.920 回答
-1

这对我有用

Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
            shareIntent.setType("image/jpeg");

            shareIntent.putExtra(android.content.Intent.EXTRA_SUBJECT, getResources().getString(R.string.share_subject));
            shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, getResources().getString(R.string.share_message));

            shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(yourimagepath);

            startActivity(Intent.createChooser(shareIntent, "Share Image"));
于 2015-11-24T08:12:08.957 回答