3

根据 CakePHP BelongsToMany 约定,我有两个表productsproduct_categories它们通过第三个表关联(编辑:这些关联是在和中建立的)。我想生成一个产品类别列表,使用最畅销产品的图像来代表每个类别。products_categories_productsProductsTable.phpProductCategoriesTable.php

我可以使用以下功能实现我想要的结果:

public function findImages(Query $query, array $options) {
    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => '(SELECT Products.image
        FROM product_categories_products AS ProductCategoriesProducts
        LEFT JOIN products AS Products
        ON ProductCategoriesProducts.product_id = Products.id
        WHERE ProductCategoriesProducts.product_category_id = ProductCategories.id
        ORDER BY Products.turnover DESC
        LIMIT 1)'
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);
    return $query;
}

这是可以接受的,还是有一种更轻松的方式来实现我的目标?我真的找不到任何关于在 CakePHP 3 中制作子查询的主题。经过几个小时的挫折后,我偶然发现了上述解决方案。任何建议表示赞赏!

4

1 回答 1

6

感谢用户 ndm_yesterday 的链接,我生成了以下解决方案:

public function findImages(Query $query, array $options) {
    $this->hasMany('ProductCategoriesProducts');

    $subquery = $this->ProductCategoriesProducts->find('all')->select([
        'Products.image'
    ])->join([
        [
            'table'     => 'products',
            'alias'     => 'Products',
            'type'      => 'LEFT',
            'conditions'=> [
                'ProductCategoriesProducts.product_id = Products.id'
            ]
        ]
    ])->where([
        'ProductCategoriesProducts.product_category_id = ProductCategories.id'
    ])->order([
        'Products.turnover' => 'DESC'
    ])->limit(1);

    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => $subquery
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);

    return $query;
}
于 2015-11-29T15:16:37.200 回答