我正在尝试使用 hibernate 将数据插入数据库。这是我将如何执行该操作
session.beginTransaction();
pojo.StuDetails stu = new StuDetails();
stu.setFName(f_name);
stu.setLName(l_name);
stu.setSex(sex);
stu.setDob(dob);
pojo.Subject sub = new Subject(subject, day, time);
pojo.SubjectHasStuDetails shs = new SubjectHasStuDetails(stu, sub);
session.save(shs);
session.getTransaction().commit();
但它给了我一个错误说
线程“主”org.hibernate.TransientPropertyValueException 中的异常:非空属性引用了一个瞬态值 - 瞬态实例必须在当前操作之前保存
这是我的学生详细信息实体
public class StuDetails implements java.io.Serializable {
private Integer id;
private String FName;
private String LName;
private String sex;
private String dob;
private Set subjectHasStuDetailses = new HashSet();
...
//constructors and getters, setters
我的学生详细信息 hbm.xml
<hibernate-mapping>
<class name="pojo.StuDetails" table="stu_details" catalog="laravel_test" optimistic-lock="version">
<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="identity" />
</id>
<property name="FName" type="string">
<column name="f_name" length="45" not-null="true" />
</property>
<property name="LName" type="string">
<column name="l_name" length="45" not-null="true" />
</property>
<property name="sex" type="string">
<column name="sex" length="45" not-null="true" />
</property>
<property name="dob" type="string">
<column name="dob" length="45" not-null="true" />
</property>
<set name="subjectHasStuDetailses" table="subject_has_stu_details" inverse="true" lazy="true" fetch="select">
<key>
<column name="stu_details_id" not-null="true" />
</key>
<one-to-many class="pojo.SubjectHasStuDetails" />
</set>
</class>
</hibernate-mapping>
我的主题实体看起来像
public class Subject implements java.io.Serializable {
private Integer id;
private String subName;
private String day;
private String time;
private Set subjectHasStuDetailses = new HashSet();
...
//constructors and getters, setters
主题.hbm.xml
<hibernate-mapping>
<class name="pojo.Subject" table="subject" catalog="laravel_test" optimistic-lock="version">
<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="identity" />
</id>
<property name="subName" type="string">
<column name="sub_name" length="45" not-null="true" />
</property>
<property name="day" type="string">
<column name="day" length="45" not-null="true" />
</property>
<property name="time" type="string">
<column name="time" length="45" not-null="true" />
</property>
<set name="subjectHasStuDetailses" table="subject_has_stu_details" inverse="true" lazy="true" fetch="select">
<key>
<column name="subject_id" not-null="true" />
</key>
<one-to-many class="pojo.SubjectHasStuDetails" />
</set>
</class>
</hibernate-mapping>
这是 SubjetcHasStuDetails 实体
public class SubjectHasStuDetails implements java.io.Serializable {
private Integer id;
private StuDetails stuDetails;
private Subject subject;
...
//constructors and getters, setters
SubjectHasStuDetials.hbm.xml
<hibernate-mapping>
<class name="pojo.SubjectHasStuDetails" table="subject_has_stu_details"
catalog="laravel_test" optimistic-lock="version">
<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="identity" />
</id>
<many-to-one name="stuDetails" class="pojo.StuDetails" fetch="select">
<column name="stu_details_id" not-null="true" />
</many-to-one>
<many-to-one name="subject" class="pojo.Subject" fetch="select" >
<column name="subject_id" not-null="true" />
</many-to-one>
</class>
</hibernate-mapping>
有人可以帮我解决这个错误吗...谢谢..