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使用 Xcode 7.1、Swift 2.0

我在 Swift 上工作，目前正在尝试将 PayU Money 支付集成到 iOS 应用程序中（遵循本文档）。

我发现很难理解完成块，而且文档都在目标 C 中。有人可以帮我解决这个问题吗？

我不是编程方面的专业人士，所以只是想确保我正在做写的事情。

这是我的代码：

import UIKit


class ViewController: UIViewController {

var paymentParamForPassing = PayUModelPaymentParams()
var webServiceResponse: PayUWebServiceResponse = PayUWebServiceResponse()
var createRequest: PayUCreateRequest = PayUCreateRequest()



override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.



    paymentParamForPassing.key = "0MQaQP"
     paymentParamForPassing.transactionID = "Ywism0Q9XC88qvy";
     paymentParamForPassing.amount =  "10.0"
     paymentParamForPassing.productInfo =  "Nokia";
     paymentParamForPassing.firstName =  "Ram";
     paymentParamForPassing.email =  "email testsdk1.com";
     paymentParamForPassing.userCredentials =  "ra:ra";
     paymentParamForPassing.phoneNumber =  "1111111111";
     paymentParamForPassing.SURL =  "https://payu.herokuapp.com/ios_success";
     paymentParamForPassing.FURL =  "https://payu.herokuapp.com/ios_failure";
     paymentParamForPassing.udf1 =  "u1";
     paymentParamForPassing.udf2 =  "u2";
     paymentParamForPassing.udf3 =  "u3";
     paymentParamForPassing.udf4 =  "u4";
     paymentParamForPassing.udf5 =  "u5";
     paymentParamForPassing.environment = ENVIRONMENT_MOBILETEST
     paymentParamForPassing.offerKey =  "offertest 1411";

     paymentParamForPassing.hashes.paymentHash =  "ade84bf6dd9da35d0aab50a5bf61d6272ab0fc488b361b65c66745054aacf1900e3c60b5022d2114bae7360174ebcb3cd7185a5d472e5c99701e5e7e1eccec34";
     paymentParamForPassing.hashes.paymentRelatedDetailsHash =  "915299224c80eff0eb2407b945a5087556292f58baca25fd05a0bceb6826aa9eb531810001dd4b4677dd928dd60d39eecf843b2189f213f9bb82c5a9483e3aac";
     paymentParamForPassing.hashes.VASForMobileSDKHash =  "5c0314c2781876f7e0a53676b0d08e1457dafe904d2d15d948626b57409538d51093eef4f15c792b1b9651be7b5659efdd45926e43a1145d68cea094687011ca";
     paymentParamForPassing.hashes.deleteUserCardHash =  "03e10e892005755f91061121036fb1b10f46202b4138d182f153c5de5c7fd44930ed94b32fac230e59bac1e4ca123aca3297e4b9d25024bf13237db9721fec1a";
     paymentParamForPassing.hashes.offerHash =  "1e99fdb59bd91c1a85624104c0fcfae34d7fcb850dd17a0b75e7efe49857d15fdefc47dd0d86ca34cbc3a8b580839aea6341a573e4e60dc1ddcf7ecc32bf9cae";


}

我在下面的 paymentButtonPressed 内的“createRequest ...”行收到以下警告

我收到以下错误

无法将类型“（NSMutableURLRequest，String，NSError？）->（）”的值转换为预期的参数类型“completionBlockForCreateRequestWithPaymentParam！”

@IBAction func paymentButtonPressed(sender: AnyObject) {
    createRequest.createRequestWithPaymentParam(paymentParamForPassing, forPaymentType: PAYMENT_PG_PAYU_MONEY, withCompletionBlock: {(request: NSMutableURLRequest, postParam: String, error: NSError?) in

        if error == nil {
            print("Success")
        }
        else {
            print("Fail")
        }

    })

}




override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

有人知道我在做什么错吗？

4

2 回答 2

0

完成块的签名与 PayUCreateRequest 类中的声明不匹配。

您使用了以下代码：

带有完成块：

 {(request: NSMutableURLRequest, postParam: String, error: NSError?)

错误是 NSString 类型。您可以改用以下行。

带有完成块：

{(request: NSMutableURLRequest, postParam: String, error: String)

我希望它可以帮助你。

于 2015-11-23T04:21:49.707 回答
0

我在这方面工作。你可以使用这个。这解决了错误。

createRequest.createRequestWithPaymentParam(paymentParamForPassing,forPaymentType: PAYMENT_PG_PAYU_MONNEY , withCompletionBlock: {(request, postParam , error) in
        if error == nil {
            print("Success")
        }
        else
        {
            print("Error data : \(error.debugDescription)")
            print("Failure")
        }
    })
于 2015-11-25T06:14:24.967 回答