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There have been a number of questions about serializing and deserializing arrays using DataContractJsonSerializer (including one from me: How can I serialise a string array to JSON using DataContractJsonSerializer?) but none seem to answer the current problem that I'm having.

I am converting an XML string to a JSON string by deserializing the XML to a DataContract object and then serializing that object to JSON, using DataContractJsonSerializer. My approach is the same as I have used on a number of other objects, all of which are serializing to JSON perfectly, but I have an object in which an array property is always rendered as null after serialization.

The classes are defined as follows:-

[DataContract]
public class Order
{
    [DataMember(Name = "consignments")]
    [XmlElement("consignments")]
    public Consignment[] Consignments { get; set; }
}

[DataContract]
public class Consignment
{
    [DataMember(Name = "conh_id")]
    [XmlElement("conh_id")]
    public string ConsignmentHeaderId { get; set; }

    [DataMember(Name = "conh_status")]
    [XmlElement("conh_status")]
    public string ConsignmentHeaderStatus { get; set; }

    [DataMember(Name = "consignmententries")]
    [XmlElement("consignmententries")]
    public ConsignmentEntry[] ConsignmentEntries { get; set; }
}

The XML I'm using looks like this:-

<order>
  <consignments>
    <consignment>
      <conh_id>A19708176</conh_id>
      <conh_status>ACCEPTED</conh_status>
      <consignmententries>
        <consignmententry>
          <conl_lineNbr>10000</conl_lineNbr>
          <conl_sku>SEC01XXZBUXXX</conl_sku>
          <conl_original_qty>1</conl_original_qty>
        </consignmententry>
      </consignmententries>
    </consignment>
  </consignments>
</order>

The deserializing and serializing is done in the following methods:-

private object DeserialiseXml(string xml)
{
    var serialiser = new XmlSerializer(typeof(Order));
    var stringReader = new StringReader(xml);
    var result = serialiser.Deserialize(stringReader);

    return result;
}

private string SerialiseJson(object serialisable)
{
    using (MemoryStream stream = new MemoryStream())
    {
        var serialiser = new DataContractJsonSerializer(serialisable.GetType());
        serialiser.WriteObject(stream, serialisable);
        var json = Encoding.UTF8.GetString(stream.ToArray());

        return json;
    } 
}

When I test it, the Consignments property is always null in the resulting JSON.

"order": {
  "consignments": [
    {
      "conh_id": null,
      "conh_status": null,
      "consignmententries": null
    }
  ]
}

Debugging shows that this property is null in the object created after the deserialization step so the problem is in the XML deserialization rather than the JSON serialization.

What do I need to change on my object model to get the array converted properly?

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1 回答 1

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当您从 XML 反序列化而不是序列化为 JSON 时，您的问题就会发生。在您的 XML 中，集合已按两个级别进行序列化：外部容器元素和每个项目的元素：

  <consignments>
    <consignment>
       <!-- Consignment data -->
    </consignment>
  </consignments>

和

  <consignmententries>
    <consignmententry>
       <!-- Entry data -->
    </consignmententry>
  </consignmententries>

（为了比较，在链接的问题中，LabelsXML 集合只有一个级别）。因此，您需要使用[XmlArray(string name)]并[XmlArrayItem(string itemName)]指定外部和内部元素名称：

[DataContract]
[XmlRoot("order")]
public class Order
{
    [DataMember(Name = "consignments")]
    [XmlArray("consignments")]
    [XmlArrayItem("consignment")]
    public Consignment[] Consignments { get; set; }
}

[DataContract]
public class Consignment
{
    [DataMember(Name = "conh_id")]
    [XmlElement("conh_id")]
    public string ConsignmentHeaderId { get; set; }

    [DataMember(Name = "conh_status")]
    [XmlElement("conh_status")]
    public string ConsignmentHeaderStatus { get; set; }

    [DataMember(Name = "consignmententries")]
    [XmlArray("consignmententries")]
    [XmlArrayItem("consignmententry")]
    public ConsignmentEntry[] ConsignmentEntries { get; set; }
}

相反，将属性添加[XmlElement]到集合告诉XmlSerializer集合应该在没有外部容器元素的情况下进行序列化。

您还需要添加[XmlRoot("order")]toOrder以指定根元素名称。

现在您的 XML 将成功反序列化。

于 2015-11-18T17:28:26.510 回答