0

对于像这样的简单案例,Springfox 无法正确生成 swagger 文档:

GET /api/departments - Gets all department

GET /api/departments?name=IT - Gets a department with name passed as query parameter

这是弹簧控制器:

@ApiOperation(value = "Gets all departments", notes = "", tags = {"departments"})
@RequestMapping(value="/departments", produces=MediaType.APPLICATION_JSON_VALUE, method=RequestMethod.GET)
public List<Department> getAllDepartments(){
       ...
}

@ApiOperation(value = "Gets a department by name", notes = "", tags = {"departments"})
@RequestMapping(value="/departments", params="name", produces=MediaType.APPLICATION_JSON_VALUE, method=RequestMethod.GET)
public Department getDepartmentByName(@RequestParam String name){
    ...
}

生成的 swagger 文件仅包含 GET /api/departments 条目,而不是带有查询过滤器的条目的踪迹。

任何解决方法?

招摇配置:

@Bean
public Docket departmentsV1Api() {
    return new Docket(DocumentationType.SWAGGER_2)
        .select()
        .apis(RequestHandlerSelectors.any())
        .paths(PathSelectors.regex("/.*"))                
        .build()
        .apiInfo(new ApiInfo("Departments Rest API","","v1","","","",""))
        .pathMapping("/api")
        .securitySchemes(newArrayList(apiKey()))
        .securityContexts(newArrayList(securityContext()))
        .groupName("departmentsV1");
}
4

1 回答 1

3

规范不支持此用例。但是,您可以使用您的enableUrlTemplating(true)方法docket来启用 rfc6570 支持。

还有一个实验库 ( springfox-swagger-ui-rfc6570 ) 可以用作标准的替代品springfox-swagger-ui

注意:请记住,这是在孵化中,并且在规范中添加支持时可能会发生变化。

于 2015-11-25T16:36:59.107 回答