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Hiya 我正在尝试为基本的 1D Monte-Carlo 集成编写代码。为此，我需要一个伪随机数列表，然后我可以将其输入到一个函数中（存储在另一个子程序中）。我已经给随机数列表一个指针，但是当我尝试在 main 中取消引用它时，我得到 "error: incompatible types when assignment to type 'double[11]' from type 'double'" 。谁能告诉我哪里出错了？我的代码可以在这里找到：

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <time.h>
#ifndef RAND_MAX
#define RAND_MAX 2147483648
#endif
#define N 10

double function(double x);
double* rdm(void);

void main(void)
{
   double* Random_number_list;
   int i;
   double sum = 0.0, sum2 = 0.0, X[N+1],S, Random_number_list2[N + 1];
   double F[N+1], lower, upper, avg, avg2;
   printf("Lower Bound:  ");
   scanf("%lf", &lower);
   printf("Upper Bound:  ");
   scanf("%lf", &upper);

   Random_number_list2 = *Random_number_list;

   for (i = 0; i <= N; i++) {
      X[i] = ((upper - lower)*Random_number_list2[i]) + lower;
      F[i] = function(X[i]);
      sum = sum + F[i];
      sum2 = sum2 + (F[i] * F[i]);
   }
   avg = sum / N;
   avg2 = sum2 / N;
   S = (upper - lower) * (avg + sqrt((avg2 - (avg * avg)) / N));
   printf("The Monte Carlo approximation is %lf\n", S);  
}

double function(double x)
{
   double y;
   y = sin (x);
   return y;
}

double* rdm(void)
{
   double* Random_number_list = calloc(N + 1, sizeof(double));
   int i;

   srand(time(NULL));
   for (i = 1; i <= N; i++) {
      Random_number_list[i] = (float) rand() / (float) RAND_MAX;
   }
   return Random_number_list;
}

非常感谢。杰克混合泳

4

1 回答 1

4

鉴于：

 int * a;
 int b[5];

然后你可以写：

 a = b;  // copying a pointer, same as a = &b[0];

但是，您不能写：

 b = a;  // b's memory is allocated, you cannot swap it out.

这意味着，失去 Random_number_list2，并与 just 一起工作Random_number_list。

你要：

 double* Random_number_list = rdm();

然后

 // added space, so it's clearer you're multiplying and not dereferencing.
 X[i] = ((upper - lower) * Random_number_list[i]) + lower;
于 2010-07-30T16:17:12.113 回答