我决定使用 Shiro 来保护我的 web 应用程序。我使用一个 tomcat 应用服务器、maven、hibernate 和 jsf。现在我尝试配置 Shiro,但遇到了一些问题。
这是我的文件:
---POM.xml---
<dependency>
<groupId>org.apache.shiro</groupId>
<artifactId>shiro-core</artifactId>
<version>1.0.0-incubating</version>
</dependency>
<dependency>
<groupId>org.apache.shiro</groupId>
<artifactId>shiro-web</artifactId>
<version>1.0.0-incubating</version>
</dependency>
<dependency>
<groupId>org.apache.shiro</groupId>
<artifactId>shiro-aspectj</artifactId>
<version>1.0.0-incubating</version>
</dependency>
---web.xml---
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>
javax.faces.webapp.FacesServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>welcome.xhtml</welcome-file>
</welcome-file-list>
<filter>
<filter-name>SecurityFilter</filter-name>
<filter-class>org.apache.shiro.web.servlet.IniShiroFilter</filter-class>
<init-param>
<param-name>config</param-name>
<param-value>
[main]
myrealm = com.misPartidos.web.MyRealm
</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>SecurityFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
如果我部署到服务器,我会收到以下错误消息:
ERROR: Exception starting filter ShiroFilter
java.lang.ClassNotFoundException: org.apache.shiro.web.servlet.IniShiroFilter
at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1645)
at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1491)
at org.apache.catalina.core.ApplicationFilterConfig.getFilter(ApplicationFilterConfig.java:269)
at org.apache.catalina.core.ApplicationFilterConfig.setFilterDef(ApplicationFilterConfig.java:422)
at org.apache.catalina.core.ApplicationFilterConfig.<init>(ApplicationFilterConfig.java:115)
at org.apache.catalina.core.StandardContext.filterStart(StandardContext.java:4001)
at org.apache.catalina.core.StandardContext.start(StandardContext.java:4651)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardHost.start(StandardHost.java:785)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:445)
at org.apache.catalina.core.StandardService.start(StandardService.java:519)
at org.apache.catalina.core.StandardServer.start(StandardServer.java:710)
at org.apache.catalina.startup.Catalina.start(Catalina.java:581)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:289)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:414)
30.07.2010 10:14:34 org.apache.catalina.core.StandardContext start
ERROR: Error filterStart
我的错误在哪里?我还需要实现其他东西吗?谢谢你的帮助斯文
额外的
我想了一下这个问题。我认为关键是设置领域。但是为了测试这个框架,我不想添加数据库或 ldap。我需要一个简单的解决方案...
更新
我将 web.xml 更改如下:
<init-param>
<param-name>config</param-name>
<param-value>
[main]
[users]
tom = secret, admin
paul = secret, user
[roles]
admin = *
user = *
</param-value>
</init-param>
但错误保持不变:-/